Answer:
c. y + 1 = -⅕(x - 2)
Step-by-step explanation:
To write the equation in point-slope form, we need to know the slope (m) and coordinates of a point the line passes through.
The equation would be in the form of y - b = m(x - a).
(a, b) = (2, -1)
Since the line is perpendicular to y = 5x + 3, the slope will be the negative reciprocal of 5 which is -⅕
m = -⅕.
Substitute a = 2, b = -1, and m = -⅕ into y - b = m(x - a).
Thus:
y - (-1) = -⅕(x - 2)
y + 1 = -⅕(x - 2)
The answer for #4 is C. 21x-82
Answer:
2 cis (7/6 pi)
Step-by-step explanation:
r = sqrt( a^2 + b^2)
r = sqrt (-sqrt(3) )^2 + (-1)^2)
= sqrt(3 +1)
= sqrt(4)
= 2
theta = arctan (b/a)
theta = arctan (-1/-sqrt(3))
theta = 30
but this is in the third quardrant -a and -b
so add 180
theta = 210 degrees
convert this to radians
210 * pi/180 = 210/180 * pi = 21/18 * pi = 7/6 * pi
r cis (theta)
2 cis (7/6 pi)
We have (x-4)/(-6-4) = (y-4)/(-4-4);
(x-4)/(-10) = (y-4)/(-8);
(x-4)/5 = (y-4)/4;
4x-16 = 5y-20;
4x - 5y + 4 = 0;
Answer:
2. D
3. B
Step-by-step explanation:
