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3 years ago

13

Make g the subject of the formula

title="w = 7 - \sqrt{g} " alt="w = 7 - \sqrt{g} " align="absmiddle" class="latex-formula">

2 answers:

Firdavs [7]3 years ago

6 0

$\text{The domain:}\\\\g\geq0\\\\7-\sqrt{g}=w\ \ \ |-7\\\\-\sqrt{g}=w-7\ \ \ |\text{change the signs}\\\\\sqrt{g}=-w+7\\\\\sqrt{g}=7-w\ \ \ \ |^2\\\\(\sqrt{g})^2=(7-w)^2\\\\\boxed{g=(7-w)^2}$
$\text{Use:}\\(a-b)^2=a^2-2ab+b^2\\\\(7-w)^2=7^2-2\cdot7\cdot w+w^2=49-14w+w^2\\\\\boxed{Answer:\ g=49-14w+w^2}$

sasho [114]3 years ago

4 0

$w=7- \sqrt{g} \ \ \Rightarrow \ \ \sqrt{g} =7-w\ \ \Rightarrow \ \ \boxed{g =(7-w)^2 }$

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Which of the following is a like radical to RootIndex 3 StartRoot 6 x squared EndRoot? x (RootIndex 3 StartRoot 6 x EndRoot) 6 (

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Answer:

4 (RootIndex 3 StartRoot 6 x squared EndRoot) = 4 $\sqrt[3]{6x^2}$

Step-by-step explanation:

<em>Added radical forms to the question for better visibility.</em>

Which of the following is a like radical to RootIndex 3 StartRoot 6 x squared EndRoot = $\sqrt[3]{6x^2}$ ?

x (RootIndex 3 StartRoot 6 x EndRoot) = x $\sqrt[3]{6x}$
6 (RootIndex 3 StartRoot x squared EndRoot) = 6 $\sqrt[3]{x^2}$
4 (RootIndex 3 StartRoot 6 x squared EndRoot) = 4 $\sqrt[3]{6x^2}$
x (RootIndex 3 StartRoot 6 EndRoot) = x $\sqrt[3]{6}$

<h3>Solution</h3>

<em>Like radicals are radicals that have the same root number and expression under the root.</em>

1) x $\sqrt[3]{6x}$ = $\sqrt[3]{6x^4}$

No, incorrect

2) 6 $\sqrt[3]{x^2}$ = $\sqrt[3]{6^3x}$

No, incorrect

3) 4 $\sqrt[3]{6x^2}$

Yes, correct

4) x $\sqrt[3]{6}$ = $\sqrt[3]{6x^3}$

No, incorrect

Compared with the given radical, we can see from the given choices only 3rd choice is like radical with $\sqrt[3]{6x^2}$

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