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2 years ago

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In my closet I have 7 pairs of jeans and 4 pairs of slacks. I need to pack 6 of these items on vacation. In how many different w

ays could I pack at least 4 pairs of jeans?

1 answer:

jeka57 [31]2 years ago

3 0

You can have 3 ways.................... ;)

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I need help with this

Alexus [3.1K]

Answer:

i don't know

Step-by-step explanation:

6 0

3 years ago

4X-8 + 6x +13= 90 ¿cual es le resultado ?

eimsori [14]

4x - 8 + 6x + 13 = 90
4x + 6x = 90 + 8 - 13
10 x = 85
10x/10 = 85/10
x = 8.5

4 0

2 years ago

Sharon's Floral Shop needs to mail 959 checks to the bank. If they can put 3 checks in each envelope, how many checks will be in

miskamm [114]

Answer:

2 checks in the final envelope

Step-by-step explanation:

359 divided by three is 319,6

319 x 3 + 357

359 - 357 = 2

I hope this was helpful!

6 0

2 years ago

Read 2 more answers

Find all the values of x in the set of complex numbers that satisfy the following equation:

Fynjy0 [20]

Compute all the component integrals first:

$I_1=\displaystyle\int_0^{\pi/4}2\sec x\,\mathrm dx=2\ln(\sqrt2+1)$
$I_2=\displaystyle\int_0^2\ln x\,\mathrm dx=2(\ln2-1)$
$I_3=\displaystyle\lim_{a\to\infty}\int_{-a}^a\frac{\mathrm dx}{x^2+1}=\pi$

Now,

$\sqrt2\approx1.4\implies \sqrt2+1\approx2.4$
$\implies \left\lceil I_1\right\rceil=2$

$e$
$\implies\left\lfloor I_2\right\rfloor=-1$

$\pi\approx3.14\implies\left\lceil I_3\right\rceil=4$

So the given equation reduces to

$\displaystyle\sum_{k=-1}^2\frac{\mathrm d}{\mathrm dx}x^{k+2}=1-4!$
$\dfrac{\mathrm dx}{\mathrm dx}+\dfrac{\mathrm dx^2}{\mathrm dx}+\dfrac{\mathrm dx^3}{\mathrm dx}+\dfrac{\mathrm dx^4}{\mathrm dx}=-23$
$4x^3+3x^2+2x+24=0$

a fairly standard cubic. Incidentally, when $x=-2$ , the LHS reduces to 0, so $x+2$ is a factor of the cubic. You can find the remaining two solutions easily with the quadratic formula.

5 0

3 years ago

The blueprint (a scale drawing used by architects and others) for Zahra’s new office measures `4` cm long and `2` cm wide. The s

Dimas [21]

Using scale concepts, it is found that the length of her office is of 10 ft, while the width is of 5 ft.

------------------------

The scale of 6 cm to 15 ft means that each <u>6 cm in the drawing represent 15 ft in actual dimensions</u>.
From this, a rule of three is applied to find the dimensions.

First, we find the actual length:

6 cm - 15 ft

4 cm - x ft

$6x = 60$

$x = \frac{60}{6}$

$x = 10$

The actual length is of 10 ft.

Then, we find the actual width:

6 cm - 15 ft

2 cm - x ft

$6x = 30$

$x = \frac{30}{6}$

$x = 5$

The actual width is of 5 ft.

A similar problem is given at brainly.com/question/24743277

6 0

2 years ago