[see picture link]Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
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We want to get the expected value for the given experiment. We will see that the expected value is $2.33
For an experiment with outcomes {x₁, ..., xₙ} each one with probability {p₁, ..., pₙ} the expected value is defined as:
EV = x₁*p₁ + ... + xₙ*pₙ
Here we have 3 outcomes:
- x₁ = winning $8
- x₂ = winning $2
- x₃ = winning $0.
For x₁ we need to roll a 6, this is a probability of 1 out of 6, then:
p₁ = 1/6
For x₂ we need to roll a 3, 4, or 5 (3 out of 6), then:
p₂ = 3/6
For x₃ we need to roll a 1 or a 2 (2 out of 6) so the probability is:
p₃ = 2/6
Then the expected value is:
EV = $8*(1/6) + $2*(3/6) + $0*(2/6) = $2.33
If you want to learn more about expected values, you can read:
brainly.com/question/15858152
Answer:
I was going to answer but nevermind
Step-by-step explanation:
Answer:
subtract one for heart drawn without replacement leaves 51 cards on which thirteen are clubs. probability of drawing club 13/51. After drawing a heart as first card there are 51 cards left and 13 of them are clubs. So the probability on drawing a club then equals 13/51