Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

Using this rule, we get



Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
Step-by-step explanation:
just think it through :
0.4x + 20 < 200
0.4x < 180
x < 180/0.4 = 450
so, x < 450
they must order less than 450 bars.
therefore, the first answer option is correct :
they can order from 0 to 449 bars, but no more.
Answer:
1/10 or 0.1 or 10%
Step-by-step explanation:
5+4 ÷2+3 or 5+2+3. you have to follow the order of PEMDAS..
P(arenthesis)
E(xponents)
M(ultiplication)
D(ivision)
A(ddition)
S(ubtraction)
Answer:
m is greater than or equal to -1, m is less than or equal to -10
Step-by-step explanation:
-1+-10