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OLEGan [10]
1 year ago
11

I need help with this if anyone can help

Mathematics
2 answers:
horsena [70]1 year ago
6 0

Answer: 2-i

Step-by-step explanation:

First, we can substitute i for x. Whenever there is x in the equation, we will put i. Now, we have f(i)=i^3-2i^2. Since i is \sqrt{-1}, i cubed would be -i, and i squared would be -1. Our equation in now -i-2(-1). We can simplify -2(-1) and get 2. Our final equation is -i+2, or in standard form, 2-i.

Fiesta28 [93]1 year ago
3 0

Answer: \Large\boxed{Fourth~Choice.~f(x)=2-i}

Concept:

Here, we need to know the power of imaginary numbers

i = √(-1)

i² = -1

i³ = -i

i⁴ = 1

Solve:

<u>Given function expression</u>

f(x)=x^3-2x^2

<u>Given the requirement of the question</u>

To find the expression for f(i)

<u>Substitute values into the expression</u>

f(x)=(i)^3-2(i)^2

<u>Simplify the exponents</u>

f(x)=(-i)-2(-1)

<u>Expand the parenthesis</u>

f(x)=-i-(-2)

\Large\boxed{f(x)=2-i}

Hope this helps!! :)

Please let me know if you have any questions

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