Question

I need help with this if anyone can help

Answer 1

Answer: 2-i

Step-by-step explanation:

First, we can substitute i for x. Whenever there is x in the equation, we will put i. Now, we have $f(i)=i^3-2i^2$. Since i is $\sqrt{-1}$, i cubed would be -i, and i squared would be -1. Our equation in now -i-2(-1). We can simplify -2(-1) and get 2. Our final equation is -i+2, or in standard form, 2-i.

Answer 2

Answer: $\Large\boxed{Fourth~Choice.~f(x)=2-i}$

Concept:

Here, we need to know the power of imaginary numbers

i = √(-1)

i² = -1

i³ = -i

i⁴ = 1

Solve:

Given function expression

$f(x)=x^3-2x^2$

Given the requirement of the question

To find the expression for f(i)

Substitute values into the expression

$f(x)=(i)^3-2(i)^2$

Simplify the exponents

$f(x)=(-i)-2(-1)$

Expand the parenthesis

$f(x)=-i-(-2)$

$\Large\boxed{f(x)=2-i}$

Hope this helps!! :)

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