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2 years ago

1.07 option 1 -- laboratory techniques lab report anybody got this lab filled out for me?

1 answer:

8 0

For this reason, chromatographic methods such as liquid, gas, or high-performance liquid chromatography are typically used in laboratories, with spectroscopic methods such as UV-visible spectroscopy, NMR, or MS being used for detection.

<h3>What purpose do laboratory methods serve?</h3>

The use of laboratory methods is crucial to a researcher's career. These abilities are essential for carrying out various studies and examinations. One cannot use these strategies in projects or research without the necessary understanding. The majority of experiments require these procedures.

<h3>An lab report is what?</h3>

A lab report describes an experiment and any findings that were made as a result of the experiment. The three major goals of a lab report are to: clearly explain the results of an experiment by giving data. talk about the outcomes.

<h3>What is the name of a lab report?</h3>

Experimental reports, commonly referred to as "lab reports," are summaries of the writers' own empirical study. An experimental report should be viewed as a "narrative" of your research that guides the reader through your experiment.

learn more about the lab here

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The value of the atomic mass of an atom is

Triss [41]

I’m going to say B:)

4 0

3 years ago

given a k value of 0.43 for the following aqueous equilibrium suppose sample z is placed into water such that its original conce

serious [3.7K]

Answer:

Less than 0.033 M:

$[Z]_{eq}=2.4x10^{-3}M$

Explanation:

Hello,

In this case, the described equilibrium is:

$2A+B\rightarrow 2Z$

Thus, the law of mass action is:

$K=\frac{[Z]^2}{[A]^2[B]}=0.43$

Nevertheless, given the initial concentration of Z that is 0.033 M, we should invert the equilibrium since the reaction will move leftwards:

$\frac{1}{K}=\frac{[A]^2[B]}{[Z]^2}=\frac{1}{0.43}=2.33$

Know, by introducing the change $x$ due to the reaction extent, we can write:

$2.33=\frac{(2x)^2*x}{(0.033-2x)^2}$

Which has the following solution:

$x_1=2.29M\\x_2=0.0181M\\x_3=0.0153M$

But the correct solution is $x_3=0.0152M$ since the other solutions make the equilibrium concentration of Z negative which is not possible. In such a way, its concentration at equilibrium is:

$[Z]_{eq}=0.033M-2(0.0153M)$

$[Z]_{eq}=2.4x10^{-3}M$

Which is clearly less than 0.033 M since the addition of a product shift the reaction leftwards in order to reestablish equilibrium (Le Chatelier's principle).

Regards.

6 0

3 years ago

- a) write the formula unit of calcium fluoride.

8090 [49]

Answer:

hope this image is helpful for you

5 0

3 years ago

Write the dissociation of hydrosulfuric acid

Vesnalui [34]

Answer:

Explanation:

Hydrosulfuric acid (H_2S) is considered a 'weak acid." It dissociates in water according to this reaction: H_2 S(aq) + H_2O(t) HS^-(aq) + H_3O^+(aq) k_a = 9 times 10^-8 Hydroiodic acid (HI) is considered a "strong acid".

7 0

3 years ago

Aluminum and oxygen react according to the following equation: 4Al(s) 3O2(g) --> 2Al2O3(s) What mass of Al2O3, in grams, can

algol [13]

Answer:

8.66 g of Al₂O₃ will be produced

Explanation:

4Al (s) + 3O₂ (g) → 2Al₂O₃ (s)

This is the reaction.

Problem statement says, that the O₂ is in excess, so the limiting reactant is the Al. Let's determine the moles we used.

4.6 g / 26.98 g/mol = 0.170 moles

Ratio is 4:2.

4 moles of aluminum can produce 2 moles of Al₂O₃

0.170 moles of Al, may produce (0.170 .2)/ 4 = 0.085 moles

Let's convert the moles of Al₂O₃ to mass.

0.085 mol . 101.96 g/mol = 8.66 g

3 0

3 years ago

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