Hello there!
The answer is:
3.1
1.3
.31
.13
Answer:
Option 1: 0.32
Step-by-step explanation:
Let
P(A) be the experimental probability of getting two
And
P(B) be the experimental probability of getting three
The dice is rolled 360 times.
So the sample space is n(S) = 360
P(A) = n(A)/n(S)
= 54/360
= 0.15
And
P(B) = n(B)/n(S)
= 62/360
= 0.172
As both the events A and B are mutually exclusive,
P(A or B) = P(A) + P(B)
= 0.15 + 0.172
=0.322
Rounding of to one decimal gives us:
0.32
So the probability of rolling a two or three is 0.32 ..
Answer:
Step-by-step explanation:
b. p(10.5<x<11.2)= p(x<11.2)-p(x<10.5)
p(x<11.2)= (11.2-9.7)/1 = 1.5 = 0.9332
p(x<10.5)= (10.5-9.7)/1= .8= 0.7881
.9332-0.7881= .1451
c. 9.7-.253, 9.7+.253
9.447, 9.953
11 hours bc 5 times 11 equals 55
X^2-6x+9=0 has only one solution
Hope this helps
