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inn [45]
2 years ago
14

The sodium amytal test involves the injection of a small amount of sodium amytal into the carotid artery on one side of the neck

. This injection?
Biology
1 answer:
romanna [79]2 years ago
6 0

The sodium amytal test involves the injection of a small amount of sodium amytal into the carotid artery on one side of the neck. This injection anesthetizes the hemisphere on that side for a few minutes.

A method that involves injecting a small amount of a barbiturate into the carotid artery on one side of the head to assess hemispheric functions, usually memory and language. The cerebral hemisphere that was injected selectively becomes impaired for 10 to 15 minutes during this operation.

Various cognitive tests are given while each hemisphere is seperately anaesthetized; deficiencies on these tasks imply that these functions are represented in the anaesthetized hemisphere. Prior to a temporal lobectomy, the Wada test may be utilised in cases with severe and uncontrollable epilepsy. Also known as the Wada technique, intracarotid sodium Amytal test (ISA), Wada dominance test, and intracarotid amobarbital procedure.

Learn more about sodium Amytal test (ISA) here;

brainly.com/question/5420349

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A woman with normal blood clotting ability whose father was a hemophiliac and whose mother was normal with no family history of
Alborosie

Answer:

The answer is 25%.

Explanation:

Hemophilia is a recessive illness that is x-linked.

If the husband has normal clotting ability, that means he has the dominant gene since he has only one X chromosome.

Since there is a probability that their child will have hemophilia, this means that the woman, who has 2 X chromosomes but has normal blood clotting abilities, has one dominant and one recessive hemophilia gene.

The probability that their first child will be a male is 50% and the probability that he will have hemophilia is also 50% since he will only get the Y chromosome from the father and the mother has one dominant and one recessive.

So the probability that their first child will be a son with hemophilia is 25%.

I hope this answer helps.

5 0
3 years ago
If C-1 of glucose is radiolabeled and the glucose then enters glycolysis, what percentage of the pyruvate molecules will carry t
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Answer:

50%

Explanation:

Glucose is a simple sugar with a total of 6 carbon atoms in its structure. Pyruvate has a total of three carbon atoms. Two molecules of pyruvate are obtained per glucose by glycolysis.  None of the carbon of glucose is released in the form of CO2 during glycolysis. Therefore, the radio-labeled C-1 of glucose will be the component of the carbon skeleton of one of the total of two pyruvate molecules produced during glycolysis. So, 50% of the pyruvate will exhibit radioactivity.

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In rabbits, black fur is dominant over white fur. Show the cross of a heterozygous black male with a homozygous white female.
sergejj [24]
We suppose the black fur is A and the white fur is a. The capital letter represents the dominant. Then the heterozygous black male is Aa and homozygous white female is aa. Then the offspring has two types, Aa and aa. The possibility of these two is equal and both are 50%.
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3 years ago
which person is least likely to be concerned about potential long-terms side affects of genetically modified (GM) food?
DerKrebs [107]

Explanation:

GMO foods have been known to cause many side effects and some say that it even has the chance of causing cancer.

The people who are not concerned about these side effects, are the people who are making a large profit off of selling these engineered foods.

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Answer:

try c

Explanation:

3 0
3 years ago
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