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Citrus2011 [14]
2 years ago
5

In 1995, the moose population in a park was measured to be 1800. By 1998, the population was measured again to be 2400. If the p

opulation continues to change linearly:
Find a formula for the moose population,
P
, in terms of
t
, the years since 1990.
Mathematics
1 answer:
Shalnov [3]2 years ago
6 0

The linear equation for the variation of population is p = 200t + 1800.

<h3>What is an equation?</h3>

An equation is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

The formula for an equation in intercept form will be given as below:-

y = mx + c.

It is given that In 1995, the moose population in a park was measured to be 1800. By 1998, the population was measured again to be 2400.

Write the linear equation for population variation.

p = mt + c

m = Rate of change = ( 2400 - 1800 ) / 3 = 200, put the value in the equation.

p = 200t + c

Put the values in the equation to get the value of the constant.

2400 = 200 x 3 + c

c = 2400 - 600

c =1800

The equation for the linear variation of the population is,

p = 200t + 1800

Therefore, the linear equation for the variation of the population is p = 200t + 1800.

To know more about equations follow

brainly.com/question/2972832

#SPJ1

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A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co
zubka84 [21]

Answer:

a) i The company should buy 40 gallons from dairy I and 60 gallons from dairy

ii) What is the maximum amount of​ butterfat? The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b.The excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

Step-by-step explanation:

a. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of​ butterfat?

From the question, we are told that:

Milk from dairy I costs ​$2.40 per​ gallon, Milk from dairy II costs ​$0.80 per gallon.

Let's represent:

Number of gallons of Milk from dairy I = x

Number of gallons of Milk from dairy II = y

At most ​$144 is available for purchasing milk.

$2.40 × x + $0.80 × y = 144

2.40x + 0.80y = 144........ Equation 1

x + y = 100....... Equation 2

x = 100 - y

2.40(100 - y) + 0.80y = 144

240 - 2.4y + 0.80y = 144

-1.60y = 144 - 240

-1.6y = -96

y = -96/-1.6

y = 60

From Equation 2

x + y = 100....... Equation 2

x + 60 = 100

x = 100 - 60

x = 40

Therefore, since number of gallons of Milk from dairy I = x and number of gallons of Milk from dairy II = y

The company should buy 40 gallons from dairy I and 60 gallons from dairy

II. What is the maximum amount of​ butterfat?

From the question

Dairy I can supply at most 50 gallons averaging 3.9​% ​butterfat,

50 gallons = 3.9% butterfat

40 gallons =

Cross Multiply

= 40 × 3.9/50

= 3.12%

Dairy II can supply at most 90 gallons averaging 2.9​% butterfat.

90 gallons of milk = 2.9% butter fat

60 gallons of milk =

Cross Multiply

= 60 × 2.9%/90

=1.9333333333%

≈ 1.93%

The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b. The solution from part a leaves both dairy I and dairy II with excess capacity. Calculate the amount of additional milk each dairy could produce.

Excess capacity of Diary I =

50 gallons - 40 gallons = 10 gallons

Excess capacity of Diary II =

90 gallons - 60 gallons = 30 gallons

Therefore, the excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

3 0
3 years ago
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