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Elan Coil [88]
3 years ago
7

What is the solution to the system of equations y=-3×-2 5×+2y=15

Mathematics
2 answers:
hichkok12 [17]3 years ago
8 0

Answer:

x= 19/11

y=35/11

Step-by-step explanation:

Anna007 [38]3 years ago
6 0

Answer: x = - 19

y = 55

Step-by-step explanation:

y = - 3x - 2 (1)

5x + 2y = 15 (2)

substitute y = - 3x - 2 into equation (2)

equation (2) becomes

5x + 2 (-3x - 2) = 15

5x + ( - 6x - 4) = 15

opening the bracket

5x - 6x - 4 = 15

collecting like terms

5x - 6x = 15 + 4

-x = 19

x = - 19

substituting x = - 19 into equation 1

y = - 3x - 2

y = - 3 (-19) - 2

y = 57- 2

y = 55

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For the functions f(x)=2x^2+3x+9 and g(x)=−3x+10 find (f⋅g)(x) and (f⋅g)(1)
pashok25 [27]

Step-by-step explanation:

f(x)=2x²+3x+9

g(x) = - 3x + 10

In order to find (f⋅g)(1) first find (f⋅g)(x)

To find (f⋅g)(x) substitute g(x) into f(x) , that's for every x in f (x) replace it by g (x)

We have

(f⋅g)(x) = 2( - 3x + 10)² + 3(- 3x + 10) + 9

Expand

(f⋅g)(x) = 2( 9x² - 60x + 100) - 9x + 30 + 9

= 18x² - 120x + 200 - 9x + 30 + 9

Group like terms

(f⋅g)(x) = 18x² - 120x - 9x + 200 + 30 + 9

(f⋅g)(x) = 18x² - 129x + 239

To find (f⋅g)(1) substitute 1 into (f⋅g)(x)

That's

(f⋅g)(1) = 18(1)² - 129(1) + 239

= 18 - 129 + 239

We have the final answer as

<h3>(f⋅g)(1) = 128</h3>

Hope this helps you

3 0
3 years ago
A little confused.<br><br><br> solve.
Westkost [7]

Answer:

It's number three, I'm sure.

-24\sqrt{35}

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Explain how to solve -4(1.75 + x) =18
kobusy [5.1K]

Answer:

first change any decimal to a whole. -4(175+x)=18. Then times -4 by 175 and x, -700+ 4x =18. Then add +700 to -700 which equals just 4x ,then add +700 to 18, which is 4x = 718. then divide both sides by 4 and estimate. x= 180

Step-by-step explanation:

8 0
3 years ago
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
1 year ago
Plsss help I’ll give u brainlest and 10 points
Eddi Din [679]
The answer would be B I hope this helps.
5 0
3 years ago
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