1) 2K(s) + 2H₂O(l)→ 2KOH(aq) + H₂<span>(g)
This is a single replacement reaction where K reacts with H</span>₂O , displaces the H⁺ ion in water and combines with OH⁻ to form a base.
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2) 2B</span>i(NO₃)₃(aq) + 3H₂S(g)→ Bi₂S₃(s) + 6HNO₃<span>(aq)
</span>This is a double displacement reaction where the ions are exchanged and form new compounds. Since ions are exchanged between 2 compounds its called double displacement.
3) 2HNO₃<span>(aq) + Ba(OH)</span>₂<span> → Ba(NO</span>₃<span>)</span>₂<span>(aq) + 2H</span>₂O<span>(l)
This is an acid base reaction where nitric acid and barium hydroxide react to form the respective salt and water</span>
17) 8.4 / 20 x 100
18) 20 . 0.5150
19) 6,50% because (as you said) the law of definite proportions states that regardless of the amount, a compound is always composed of the same elements in the same proportion by mass
Answer : The mass of is, 9.64 grams.
Explanation : Given,
Mass of = 54.6 g
Molar mass of = 17 g/mol
Molar mass of = 2 g/mol
First we have to calculate the moles of .
Now we have to calculate the moles of
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 2 mole of react to give 3 moles of
So, 3.21 mole of react to give mole of
Now we have to calculate the mass of
Therefore, the mass of is, 9.64 grams.
Answer:
Explanation:
The reaction produces two water molecules, so the mole ratio between oxygen and water is 1:2, but the mole ratio between water and hydrogen is 2:2.
Answer:
Mass = 88.12 g
Explanation:
Given data:
Mass of iron oxide = 126 g
Mass of iron formed = ?
Solution:
Chemical equation:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Number of moles of iron oxide:
Number of moles = mass/molar mass
Number of moles = 126 g/ 159.69 g/mol
Number of moles = 0.789 mol
Now we will compare the moles of iron with iron oxide.
Fe₂O₃ : Fe
1 : 2
0.789 : 2/1×0.789 = 1.578 mol
Mass of iron:
Mass = number of moles ×molar mass
Mass = 1.578 mol × 55.84 g/mol
Mass = 88.12 g