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vladimir2022 [97]
3 years ago
13

What is the mass percentage of carbon in 5.000 G of sucrose

Chemistry
2 answers:
stepan [7]3 years ago
6 0

Answer : The mass percentage of carbon in sucrose  is, 42.1 %

Explanation: Given,

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of O = 16 g/mole

First we have to calculate the molar mass of sucrose.

Molar mass of sucrose (C_{12}H_{22}O_{11}) = 12(12)+22(1)+11(16)=342g/mole

Now we have to calculate the mass of carbon in 5 g of sucrose.

As we now that there are 12 number of carbon atoms, 22 number of hydrogen atoms and 11 number of oxygen atoms.

The mass of carbon = 12\times 12=144g

As, 342 g of sucrose contains 144 g of carbon

So, 5 g of sucrose contains \frac{5}{342}\times 144=2.105g of carbon

Now we have to calculate the mass percentage of carbon in sucrose.

Formula used :

\%\text{ Mass percentage of carbon}=\frac{\text{Mass of carbon}}{\text{Mass of sucrose}}\times 100

Now put all the given values in this formula, we get:

\%\text{ Mass percentage of carbon}=\frac{2.105}{5}\times 100=42.1\%

Therefore, the mass percentage of carbon in sucrose  is, 42.1 %

Crank3 years ago
3 0
17) 8.4 / 20 x 100

18) 20 . 0.5150

19) 6,50% because (as you said) the law of definite proportions states that regardless of the amount, a compound is always composed of the same elements in the same proportion by mass
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For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give a
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6 0
3 years ago
A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0
3 years ago
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Answer:

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Fungsi utama kapilari ialah pertukaran bahan antara sel darah dan tisu.

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Explanation:

(translated version)

Why blood capillary walls differ from veins and arteries

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3 years ago
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