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8_murik_8 [283]
3 years ago
11

iron is made by a reduction of iron oxide with carbon monoxide. Fe2O3+3CO-2Fe+3CO2. Calculate the mass of iron that can be forme

d from 126g of iron oxide
Chemistry
1 answer:
lyudmila [28]3 years ago
4 0

Answer:

Mass = 88.12 g

Explanation:

Given data:

Mass of iron oxide = 126 g

Mass of iron formed = ?

Solution:

Chemical equation:

Fe₂O₃ + 3CO    →      2Fe + 3CO₂

Number of moles of iron oxide:

Number of moles = mass/molar mass

Number of moles = 126 g/ 159.69 g/mol

Number of moles = 0.789 mol

Now we will compare the moles of iron with iron oxide.

                      Fe₂O₃           :             Fe

                         1                 :               2

                   0.789              :            2/1×0.789 = 1.578 mol

Mass of iron:

Mass = number of moles ×molar mass

Mass = 1.578 mol × 55.84 g/mol

Mass = 88.12 g

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You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the
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The empirical formula of this compound is equal to Fe_{2}O_3.

<h3>Empirical formula</h3>

To calculate the empirical formula of a compound, it is necessary to know the number of moles present.

Therefore, we will use the molar mass of iron and oxygen to find the amount of moles, so that:

MM_O = 16g/mol\\MM_Fe = 55.8g/mol

                                        MM = \frac{m}{mol}

  • Oxygen

                                            16 = \frac{4.8}{mol}

                                            mol = 0.3

  • Iron

                                   

                                               55.8 = \frac{11.2}{mol}

                                               mol = 0.2

Finally, as the empirical formula is composed of integers numbers of moles, just multiply the values ​​by the smallest common factor to transform into an integer, so that:

                                       O =>  0.3 \times 10 = 3moles

                                       Fe => 0.2 \times 10 = 2moles

So, the empirical formula of this compound is equal to Fe_{2}O_3

Learn more about empirical formula in: brainly.com/question/1363167

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Hydrogen, since in H2O there are two hydrogen atoms per one oxygen atom. So the hydrogen atoms would run out first so that there are 12 H2O molecules, where all the hydrogen is used and there are 12 oxygen atoms left over
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