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Mars2501 [29]
3 years ago
14

Draw 2 lines to make 1 square and 2 triangles in a trapezoid

Mathematics
1 answer:
kogti [31]3 years ago
3 0
First, know which two sides are parallel. Then, go to the corners of the shorter side and draw a perpendicular line connecting to both sides
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3 kilograms of red hots and I
MrRa [10]

Answer:

Step-by-step explanation:

each kilogram of gummy bears is 9 dollars because the difference of 39 and 21 is 18, 18/2 is 9, 21-9=12 12/3=4 , therefor each kilogram of red hots is $4.00

4 0
3 years ago
Read 2 more answers
June has $1.95 in dimes and nickels. She has a total of 28 coins. how many of each type of coin does she have?
Dovator [93]

Answer:

11 dimes, 17 nickels

Step-by-step explanation:

d + n = 28, put one variable by itself on a side, d = 28 - n

.10d + .05n = 1.95

Sub the first equation into the second

.10(28 - n) + .05n = 1.95

2.8 - .10n + .05n = 1.95

2.8 - .05n = 1.95

-.05n = -0.85

n = 17 nickels

d + 17 = 28

d = 11  11 dimes

7 0
2 years ago
Read 2 more answers
A recipe calls for 5.0 qt of milk. what is this quantity in cubic centimeters?
Ede4ka [16]
To answer this question, you need to understand how to convert unit. In this case, it will be quarts(qt) into centimeter cubic(cm3). A quart is 1/4 gallon and one gallon equal to <span>3 785.4 cm3. Then the calculation would be: 
5qt of milk * 0.25 gallon/qt * </span>3 785.4 cm3/gallon= 4731.75 cm3
5 0
3 years ago
The recommended single dose for a particular drug is 100 mg. How many doses can be obtained from 20 grams of the drug?
Lisa [10]

Answer:

B. 200 doses

Step-by-step explanation:

Given,

1 dose is required for 100 mg,

Since, 1 mg = 0.001 g,

⇒ 100 mg = 0.1 g

⇒ 1 dost is required for 0.1 g,

Thus, the ratio of doses and quantity ( in gram ) is \frac{1}{0.1}=10

Let x be the doses required for 20 grams,

So, the ratio of doses and quantity is \frac{x}{20}

\implies \frac{x}{20}=10

\implies x=200

Hence, 200 doses can be obtained from 20 grams of the drug.

Option 'B' is correct.

8 0
3 years ago
Suppose each runner ran at the rate given in the table above for 3.1 miles. How much time will elapse between the first place fi
Scilla [17]
You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:

Runner         distance           time

Arabella        7,299 feet        561 seconds
Bettina          3,425 yards     13 minutes, 12 seconds
Chandra       8,214 feet        0,195 hours
Divya            1,62 miles        732 seconds

To answer the question you must find the rate for each runner and then calculate the time to run 3.1 miles at each rate.

First you need to convert the data to obtain the rate in miles per second.

These are the main conversion identities:

1 mile = 5280 feet

1 mile = 1760 yards

1 hour = 3600 seconds

1 hour = 60 minutes

1 minute = 60 seconds

Arabella:

rate: 7,229 feet / 561 seconds * (1 mile / 5280 feet)  =

= 0.00244 mile/second

Time to run 3.1 miles: V = d / t => t = d / V = 3.1 miles / 0.00244 mile/second = 1270 seconds

Bettina:

13 minutes + 12 seconds = 13*60 seconds +12 seconds = 792 seconds

rate = 3425 yards / 792 seconds * 1 mile / 1760 yards = 0.00246 mile/seconds

Time to run 3.1 miles = 3.1 miles / 0.00246 mile/second = 1260 seconds

Chandra:

rate = 8214 feet / 0.195 hours * 1 mile / 5280 feet * 1hour / 3600 seconds =

= 0.00222 seconds

Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds

Divya:

rate = 1.62 miles / 732 seconds = 0.00221 seconds

Time = 3.1 mile / 0.00221 seconds = 1403 seconds

Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds

That is equivalent to 2.38 seconds.
6 0
3 years ago
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