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dsp73
3 years ago
5

What is y=-3/10x-8 written in standard form

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0
Standard form is ax + by = c

so the answer is

-3/10x - y = 8
Usimov [2.4K]3 years ago
3 0
Put x and y on one side.

y = -3/10x - 8
Add 3/10x to both sides.
3/10x + y = -8
Because there are no fractions in Standard Form, multiply everything by 10.
3x + 10y = -80
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-8-8x^2=-31<br> how to solve for x
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Answer:

x = ± \sqrt{\frac{23}{2\sqrt{2}}}

Step-by-step explanation:

-8 - 8x^2= -31

Since this is a quadratic, it needs to be factored.

First, move the x to the other side:

-8 = 8x^2 - 31

Then, get the x alone by first adding 31:

23 = 8x^2

then dividing by 8:

x^2 = 23/8

Finally, square root both sides and remember the even roots property:

x = ± \sqrt{\frac{23}{8}}

and simplify the root 8:

x = ±  \sqrt{\frac{23}{2\sqrt{2}}}

Note: This answer may have a mistake.

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2 years ago
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Step-by-step explanation:

The discriminant, <em>b</em>² - 4<em>ac</em>, is the expression (<u><em>radicand </em></u>) of the quadratic equation:

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The value of the discriminant determines the <u>nature</u> and the <u>number of solutions</u> given by the quadratic equation.

A discriminant with a negative value (or b² - 4ac < 0 ) means that the quadratic equation has no real solutions or two complex solutions. Quadratic equations with a negative discriminant also have no x-intercepts; thus, its graph will not cross the x-axis.  

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