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2 years ago

Please help answer needed asap

Mathematics

1 answer:

Basile [38]2 years ago

5 0

Answer:

Step-by-step explanation:

a = 3n-30 solve for 'n'

a + 30 = 3n

n = (a+30)/3

n(a) = (a+30)/3

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It is 2.1 km from Mary's house to the nearest mailbox. How far is it in meters?

Nadusha1986 [10]

Answer: 2.1km in meters is 2100m

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3 years ago

Read 2 more answers

the u.s department of agriculture reported that 57 out of every 100 milk drinkers drink skim milk. if a storeowner orders 24 gal

S_A_V [24]

STEP 1:
Find percentage. 57 out of 100 is the percentage to multiply by.

57/100= 0.57 (= 57%)

STEP 2:
Multiply percentage by the total gallons ordered (24).

=24 gallons * 0.57
=13.68 gallons

ALTERNATIVE METHOD (use which works best for you)

Set up a proportion. 57 to 100 is x out of 24 gallons.

x= number skim gallons to order

57/100= x/24
cross multiply
(57*24)= (100*x)
1368= 100x
divide both sides by 100
13.68 gallons= x

ANSWER: Since you cannot order a partial gallon of milk, round up to 14 whole gallons

Hope this helps! :)

4 0

3 years ago

Multiply and simplify: (4x)(3x²)

Anettt [7]

Answer:

I think this is the right answer

C=12

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3 years ago

What is the length to one side of this triangle

garik1379 [7]

The formula of the altitude of an equilateral triangle with side x:
$h=\dfrac{x\sqrt3}{2}$
We have:
$h=6\sqrt3$
Substitute:
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4 0

3 years ago

Madison is given rectangle ABCD with one diagonal BD

Lena [83]

Answer:

i. Rotate

ii. Translates

Step-by-step explanation:

Rigid transformations are the methods required in which the orientation, dimension, position, or size of a given figure can be transformed. Some types of rigid transformation are: rotation, translation, reflection, etc.

From the given question, the two rigid transformation procedure required for Madison to prove that ΔABD ≅ ΔCDB by rigid transformations are: rotation and translation.

Madison decides to rotate ΔABD $180^{o}$ about point B to create triangle A'B'D'. Next she translates A'B'D' along diagonal BD until point B' from ΔA'B'D' lines up with point d from ΔCDB.

Therefore,

ΔABD ≅ ΔCDB

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3 years ago