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ad-work [718]
1 year ago
10

What are the quartiles of the data

Mathematics
1 answer:
MAXImum [283]1 year ago
3 0

The quartiles of the data are: 60.5,64,66

Option(b) is correct.

The quartile divides the distribution into four groups and calculates the range of values above and below the mean.

A quartile separates the dataset into four categories by dividing the data into three points: the lowest, median, and upper quartiles.

Similar to how the median divides the data in half, with 50% of the measurements falling below it and 50% falling above it, the quartile divides the data into fourths, with 25% of the measurements falling below the lower quartile, 50% falling below the median, and 75% falling below the upper quartile.

The interquartile range, a measurement of variation around the median, is calculated using quartiles.

For the given data set: 58,60,60,61,62,64,64,64,66,70,72

Median = 64

Lower quartile = Median of the lower half = 60.5

Upper quartile = Median of the upper half = 66

Learn more about quartiles here:

brainly.com/question/10005803

#SPJ1

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2+5+2) = 6(+2)
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8th Grade Math Equation. Please help! I accept any type of help!
muminat

Hello from MrBillDoesMath!

Answer:

Positive x-intercept =  + sqrt(3)

Negative x-intercept = - sqrt(3)


Discussion:

Generally, the x-intercept of a function g(x) occurs where g(x) = 0. In our case this is

g(x) = 0   =>

3x^2 - 9 = 0     =>                         (add 9 to both sides of the equation)

3 x^2      = 9    =>                         (divide both sides by 3)

x^2 = 9/3 = 3  =>

x = +\- sqrt (3)

Positive x-intercept =  + sqrt(3)

Negative x-intercept = - sqrt(3)



Thank you,

MrB

5 0
3 years ago
X2 + 17x + 42 = 0<br> solving quadratics by factoring (the solution has brackets around them)
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A ball is launched from a 682.276 meter tall platform. the equation for the ball's height h at time t seconds after launch is h(
blagie [28]

The maximum height the ball achieves before landing is 682.276 meters at t = 0.

<h3>What are maxima and minima?</h3>

Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.

We have a function:

h(t) = -4.9t² + 682.276

Which represents the ball's height h at time t seconds.

To find the maximum height first find the first derivative of the function and equate it to zero

h'(t) = -9.8t = 0

t = 0

Find second derivative:

h''(t) = -9.8

At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.

Maximum height at t = 0:

h(0) = 682.276 meters

Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.

Learn more about the maxima and minima here:

brainly.com/question/6422517

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4 0
1 year ago
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