What is the value of p in the equation below?
1 answer:
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The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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Answer:
Brand A = 21 heart-rate watches.
Brand B = 13 heart-rate watches.
Step-by-step explanation:
Let A be the number of Brand A heart watches and B be the number of Brand B heart watches.
We have been given that a nonprofit community health organization purchased 34 heart-rate watches for use at a wellness center.
We can represent this information in an equation as:
We have been given that in a certain year, brand A of heart-rate watch cost $39.99 and brand B cost $59.99 and the organization spent $1619.66 for the watches.
We can represent this information in an equation as:
We will use substitution method to solve our system of equations.
From equation (1) we will get,
Substituting in equation(2) we will get,
Therefore, the organisation purchased 13 heart-rate watches of brand B.
Now let us substitute B=13 in equation (1).
Therefore, the organisation purchased 21 heart-rate watches of brand A.