Question

A resistor connected to a 3.0 v battery dissipates 1.0 w. If the battery is replaced by a 6.0 v battery. The power dissipated by the resistor will be?

Answer 1

The power dissipated by the resistor will be = 4 watt.

Electric energy is characterized by means of present day or the drift of electric fee and voltage or the potential of rate to deliver power. A given price of strength may be produced by means of any combination of current and voltage values.

Electric strength measures the rate of electrical energy switch through an electric circuit according to unit of time and measured the usage of the SI unit of energy that is watt or one joule in step with. Electric powered energy is generally supplied by electric powered batteries and produced by way of electric mills.

voltage =  3.0 v

power = 1.o w

power = V²/R

            = 3*3/R

R = 9/1 = 9 Ω

voltage =  6.0 v

Resistance =  9 Ω

power = V²/R

           = 6*6/9 =9 Ω  =  4 watt

Power dissipated = 4 watt

The power dissipation through the resistance is calculated by substituting the value of the resistance and the voltage. The value of the resistance is same as the first case.

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