Increase; newton’s second law of motion
Answer:
16.17 m/s
Explanation:
h = 3.2 m
u = 18.1 m/s
Angle of projection, θ = 49°
Let H be the maximum height reached by the ball.
The formula for the maximum height is given by


The vertical distance fall down by the ball, h' H - h = 9.52 - 3.2 = 6.32 m
Let v be the velocity of ball with which it strikes the ground.
Use third equation of motion for vertical direction

here, uy = 0
So,

vy = 11.13 m/s
vx = u Cos 49 = 18.1 x 0.656 = 11.87 m/s
The resultant velocity is given by


v = 16.27 m/s
Note : Be careful with speed and velocity, even the formula is same that

1. If we would like to find the velocity, we must calculate the distance from initial to final,

,
2. If we would like to find the speed, we must calculate the total distance that travelled (

.
So, in this question, because it return back to its initial point so (delta)x = 0, so average velocity is 0 m/s.
A falling object will reach 49 m/s