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sukhopar [10]
3 years ago
12

Brewed coffee is often too hot to drink right away. you can cool it with an ice cube, but this dilutes it. or you can buy a devi

ce that will cool your coffee without dilution - a 150 g aluminum cylinder that you take from your freezer and place in a mug of hot coffee. part a if the cylinder is cooled to -20âc, a typical freezer temperature, and then dropped into a large cup of coffee (essentially water, with a mass of 500 g) at 85âc, what is the final temperature of the coffee?
Physics
1 answer:
Dvinal [7]3 years ago
8 0
<span>In order to answer this question you need to know the specific heat of aluminum and water. The source below says 0.900 J/g K and 4.186 J/g K respectively. Let T be the final temperature to be found: (0.900 J/g K) x (270 g) x (T - (-20))K = (243T + 4860) J gained by the Al (4.186 J/g K) x (500 g) x (85 - T)K = (177905 - 2093T ) J lost by the coffee Set the two expressions for heat gained/lost equal to each other: 243T + 4860 = 177905 - 2093T Solve for T algebraically: T = 74.1 °C</span>
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What is the simplest relationship between the angular wavenumber k and just one of the other kinematic variables?
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Answer : k=\dfrac{\omega}{k}

Explanation :

The word kinematics means the study of motion. Kinematic variables gives the description of the motion of the body.

Displacement, Velocity, acceleration and time are associated with the motion of particle.

Wavenumber is defined as the frequency of wave, which is measured in cycles per unit distance.

Wave number is also defines as:

k=\dfrac{2\pi}{\lambda}

where, \lambda is wavelength

k=\dfrac{2\pi}{\lambda}\times \dfrac{T}{T}

since, \dfrac{2\pi}{T}=\omega \ and\ \dfrac{1}{V}=\dfrac{T}{\lambda}

So, k=\dfrac{\omega}{V}

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Hence, the  relationship between the angular wavenumber k and and kinamatic variable V is

k=\dfrac{\omega}{V}

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the earth's moon has a gravitational field strength of about 1.6 n/kg near its surface. the moon has a mass of 7.35x10^22 kg. wh
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An oil film on top of water has one patch that is much thinner than the wavelength of visible light. The index of refraction of
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Answer:

they indicate that the thickness is much less than the length of anything we have a destructive interference, bone has a dark area

Explanation:

Let's analyze the interaction of the ray reflected on the surface of the oil and at the bottom of the film, to know what kind of interference we have.

- When the beam passes from the air to the oil film, it has a phase change of 180 since the refractive index of the oil is greater than the refractive index of the air n = 1

- When the beam reaches the oil-water interface, the refractive impact of the water is oil cobs, therefore it has a 180 phase change

- in the oil film because the speed of the beam is different from that of air and the frequency in the air and oil is the same, since the propagation of a resonant type process, to meet the equation

               v = λ f

The wavelength must change c = λ₀ f

               c / v = λ₀ /λ

               n = λ₀ /λ

               λₙ = λ₀ / n

In general this type of reflection is almost normal to the surface, so we can calculate the optical path difference, if t is the thickness of the film, for constructive interference

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The last two terms are for the phase change

             2t / = (m + 1) λₙ

This is the condition to see a bright beam

For the first reflection m = 0

              2t = λₙ

Therefore the minimum thickness of the film for constructive interference is λₙ / 2.

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