Answer:
600 KPa.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V1) = 0.075 m³
Final volume (V2) = 0.45 m³
Final pressure (P2) = 100 KPa
Initial pressure (P1) =?
Temperature = constant
The initial pressure can be obtained by using the Boyle's law equation as shown below:
P1V1 = P2V2
P1 × 0.075 = 100 × 0.45
P1 × 0.075 = 45
Divide both side by 0.075
P1 = 45 / 0.075
P1 = 600 KPa.
Thus, the initial pressure in the balloon is 600 KPa.
The answer is d a long ridge of sediment deposited by the longshore current and seperated from mainland
At the instant you dropped it from your hand, its speed was zero.
The coin gained 9.8 m/s every second it fell. At the end of 1.85 sec,
just before it went 'tink' onto the ground, its speed was
(9.8 m/s) x (1.85 sec) = 18.13 m/s .
Its velocity at that final instant was 18.13 m/s downward.
