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makvit [3.9K]
2 years ago
7

In year 13, the scientist will put tree wrap around tree 1 to protect it from the winter snow. The height of the tree wrap needs

to be 45 inches.
Mathematics
2 answers:
Dominik [7]2 years ago
6 0

Answer:

22 feet²

Step-by-step explanation:

We are given:

height of tree h = 45 inches

Circumference= πd × inches

But d = 22.2inches

Therefore area will be

Area = 22.2π × 45 inches²

Area = 3137 inches²

Let's convert from inches² to feet², we have:

1 foot = 12 inches.

Therefore,

1 square foot = 1foot × 1foot = 12inches×12inches

= 3137inches² / 144 inches²

= 22feet²

Note: I attached missing data which states that diameter at year 13 is 22.2inches

MatroZZZ [7]2 years ago
6 0

Answer: 22

Step-by-step explanation:

simple

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3 years ago
Which expression is equivalent to 4^6 ⋅ 4^−8? 1 over 4 to the 2nd power 1 over 4 to the 14th power 42 414
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4 0
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Write the area A of a square as a function of its perimeter P. ...?
Svetradugi [14.3K]
The answer is A = P²/16

The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s  = s²

Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.

Step 1:
P = 4s
s = P/4

Step 2:
A = s²
s = P/4
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4 0
3 years ago
10 points someone help me please!?
Soloha48 [4]

Answer:

\large\boxed{b=\sqrt{95}}

Step-by-step explanation:

Use the Pyhagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=b,\ leg=7,\ hypotenuse=12

Substitute:

b^2+7^2=12^2

b^2+49=144       <em>subtract 49 from both sides</em>

b^2=95\to b=\sqrt{95}

7 0
3 years ago
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