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1 year ago

Help Me pleaseeeeeee

Mathematics

1 answer:

maks197457 [2]1 year ago

6 0

Answer: 94x-1

Step-by-step explanation:

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Could someone please help me!!

GrogVix [38]

Answer:

Step-by-step explanation:

Intercept form

8 0

3 years ago

Find the perimeter of the figure to the nearest hundredth. due today

Marianna [84]

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Answer: 36.57

Explanation:

6x4 = 24

3.14(2)^2 = 12.56

12.57+24=36.57

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

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8 0

2 years ago

Four lines are drawn on a coordinate plane to form trapezoid WXYZ.

Degger [83]

Answer:

A.) Line WZ has the same slope as line XY.

C.) Line YX has a greater slope than line ZY.

D.) Line ZW has the same y-intercept as line YZ.

Step-by-step explanation:

6 0

3 years ago

Can you help me please?

Alexxx [7]

The errors are that she is just multiplying incorrectly.

10* 1.75 = 17.5
100* 1.75= 175
1000* 1.75 = 1750

When you are multiplying by tens (hundreds and thousands are also considered tens since they are just 10*10 and 10*10*10), you should just be moving the decimal place forward one place.
This goes back to very basic math when you are learning place values.

8 0

3 years ago

According to geologists, the San Francisco Bay Area experiences five earthquakes with a magnitude of 6.5 or greater every 100 ye

sveta [45]

Answer:

13.53% probability that no earthquakes with a magnitude of 6.5 or greater strike the San Francisco Bay Area in the next 40 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

According to geologists, the San Francisco Bay Area experiences five earthquakes with a magnitude of 6.5 or greater every 100 years.

One earthquake each 100/5 = 20 years.

What is the probability that no earthquakes with a magnitude of 6.5 or greater strike the San Francisco Bay Area in the next 40 years?

40 years, so $\mu = 40/20 = 2$

This probability is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353$

13.53% probability that no earthquakes with a magnitude of 6.5 or greater strike the San Francisco Bay Area in the next 40 years

4 0

2 years ago