Answer:

Step-by-step explanation:
Answer: y(-3y^7+18y^4+10)
Step-by-step explanation:
Answer:
12 bouquets
Step-by-step explanation:
Let there be x number of roses and x number of tulips initially at the store. Each bouquet was made with 3 roses and 4 tulips. Assume that y bouquets were made in total.
If each bouquet was made with 3 roses and 4 tulips, then y bouquets will be made with 3y roses and 4y tulips.
After the bouquets were all made, there were 30 roses and 18 tulips left in the store. This means, if we subtract number of roses that were used in bouquets from total number of roses, the result must be 30. Likewise, for tulips the result would be 18. This can be represented as:
x - 3y = 30 Equation 1
x - 4y = 18 Equation 2
Subtracting Equation 2 from Equation 1, we get:
x - 3y - (x - 4y) = 30 - 18
x - 3y - x + 4y = 12
y = 12
Since y represents the number of bouquets made, we can conclude that 12 bouquets were made in the store.
Answer:
<u>Approximately 16 tablets of medicine</u>
Step-by-step explanation:
Based on the information above , we can use a <u>Rule of Three</u> to first figure out how many mg the cat would need to ingest per day.


Now we see that the cat needs to take a daily dose of 22.5mg. Since the Tablets come at a strength of 10 mg per tablet then,

The cat would need to take 2.25 tablets per day. Since she needs to take the dose for the next 7 days then,

She would need to take<u> approximately 16 tablets of medicine</u> during the week .
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
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If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.