The given expression :

For coordinates:
put x = 0 then :

Coordinate : (x, y) = (0, 1)
Put x= 1 and simplify :

Coordinate : (x, y) = ( 1, 0.5)
Put x = (-2) and simplify :

Coordinate : (x, y) = ( -2, 4)
Put x = (-3) and simplify :

Coordinate : (x, y) = (-3, 8)
Substitute x = (-1) and simplify :

Coordinate : (x, y) = ( -1, 2)
So, the coordinates are :
The graph is :
The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at
(-1.5, -3.25).
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For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
You can use Substitution to solve this problem:
4x-y=20
-y=-4x+20
y=4x-20
Now you have two equations, and you use the first one to substitute into the second one.
y=4x-20 and -2x-2y=10
-2x-2(4x-20)=10
-2x-8x+40=10
-10x+40=10
-10x=-30
-x=-3
x=3
Now that we have figured out what x is, we can substitute x in to one of the equations to figure out y.
4x-y=20 x=3
4(3)-y=20
12-y=20
-y=8
y=-8
<em><u>So your answer would be x=3 and y=-8</u></em>
Answer: A
Step-by-step explanation: A reference angle is smallest possible angles that terminal side makes with the x- axis. Since 190 degrees is located i the 3rd quadrant we use the formula 190-180 to find the possible answer and in this case it is A, 10.
6x - 1 = 2(-6)
6x = - 11
x = - 11/6
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