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Naya [18.7K]
2 years ago
6

Consider this function. f(x)=6log2x-3 over which interval is function f increasing at the greatest rate?

Mathematics
1 answer:
m_a_m_a [10]2 years ago
6 0

The function increased at the highest rate in the interval [1/8, 1/2], as can be seen from the function value and its interval values.

<h3>What is  maxima and minima?</h3>

A function's maxima and minima are its highest and lowest values, respectively, either on the entire domain or inside a certain range. They are referred to as the function's extrema collectively. The plural forms of maximum and minimum for a function are respectively known as maxima and minima.

<h3>Why do we use maxima and minima?</h3>

The extreme values of a function—their maximum and minimum values—are referred to by the words maxima and minima. Maximum refers to the maximum value or amount that is feasible. A function's biggest value within its range is known as its absolute maximum.

<h3>According to the given information we have:</h3>

f(x)=6log2x-3

For the interval x ∈[2, 6]

f(x) ∈ [-0.678, 3]

For the interval x ∈ [1/8, 1/2]

f(x) ∈ [ -9.96, -5.32]

For the interval x ∈ [1, 2]

f(x) ∈ [-3, -0.67]

For the interval x∈ [1/2, 1]

f(x) ∈ [-5.32, -3]

The function increased at the highest rate in the interval [1/8, 1/2], as can be seen from the function value and its interval values.

To know more about  interval values visit:

brainly.com/question/14264237

#SPJ4

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Answer:

(x-8)(x+7)

Step-by-step explanation:

using quadratic formula we have

x=  \frac{-b+-\sqrt{b^{2}-4*a*c}}{2*a}

we have:

x^2-x-56=0

a= 1 b=-1 c=-56

so we have:

x=(-(-1)+-sqrt(1^1-4*(1)*(-56)))/(2*1)

x=1+-sqrt(1-4*(-56))/(2)

x=(1+-sqrt(225))/2

x=(1+-15)/2

so we have the roots:

x1=(1+15)/2 =8

x2=(1-15)/2=-7

so the answer is (x-8)(x+7)

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shusha [124]

Answer:

(2/5)*b+1 = -11 // + 11

(2/5)*b+1+11 = 0

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Step-by-step explanation:

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Step-by-step explanation:

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Explanation:

Midline: it is a horizontal line where half of the function above it and half of the function is below it.

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3) From the graph,

\begin{gathered} \text{Midline}=\frac{Maximum\text{ point+ minimum point}}{2} \\ =\frac{3+(-1)}{2} \\ =\frac{3-1}{2} \\ =\frac{2}{2} \\ =1 \end{gathered}

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1) Amplitude

\text{Amplitude =}2

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\begin{gathered} y=a\cos (b(x-c))+d \\ a=\text{ amplitude} \\ b=\text{period} \\ c=\text{ phase shift} \\ d=\text{ vertical shift} \\ y=2\cos (\frac{2\pi}{6}x)+1 \end{gathered}

Answer:

y=2\cos (\frac{2\pi}{6}x)+1

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