the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
9514 1404 393
Answer:
D. at the ballpark
Step-by-step explanation:
The y-coordinate doesn't change between points C and D. That means Daniel's distance from home is not changing. Since Daniel rode to the ballpark and back, and since segment CD represents Daniel's farthest distance from home, we conclude ...
CD represents the time Daniel spent at the ballpark.
Answer:
3 and 4
Step-by-step explanation:
Consider squares on either side of 15, that is 9 and 16, so
< 
< 
, that is
3 < < 4
Y=3/1x+-1 hope this is correct
