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Galina-37 [17]
3 years ago
7

Whats 14 4/10 - 13 1/3 ASAP

Mathematics
2 answers:
monitta3 years ago
7 0

Answer:

1 1/15

Step-by-step explanation:

dangina [55]3 years ago
4 0

Answer:

16/15  or  1.06.. or 1 1/15

Step-by-step explanation:

:)

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Follow the directions to convert the analog sound wave into a digital signal. The lines on the grid intersect at various points
Blababa [14]
I like to be ____ like a ____ 3+ 600 = 306:)
6 0
3 years ago
PLEASE HELP WITH PART B!!<br><br> can you also explain y and x, I dont understand part B &gt;
Doss [256]

A. I would suggest including <em>all</em> units in your answer. Both answers are correct but the unit is also important.

average rate of change:

($750 - $350) / (2014 - 2010) = $400 / (4 years) = $100 per year

initial value:

$350

B. Take 2010 to be year 0. Then for year <em>x</em> = 0, the fee is <em>y</em> = $350.

If the fee increases at a rate of $100 per year, this means that when <em>x</em> = 1, <em>y</em> = $350 + $100 = $450. So the graph of the function that models the dog-walking fee is a line that passes through the points (0, 350) and (1, 450), adn the slope of this line is

(450 - 350) / (1 - 0) = 100/1 = 100

which is the same as the average rate of change.

Using the point-slope formula for a line, the equation you want is then

<em>y</em> - 350 = 100 (<em>x</em> - 0)

<em>y</em> - 350 = 100<em>x</em>

<em>y</em> = 100<em>x</em> + 350

8 0
3 years ago
WILL GIVE BRAINLIEST
belka [17]

Answer:

Viewed as a right angled triangle tan(x)=512 can be thought of as the ratio of opposite ...

Step-by-step explanation:

4 0
2 years ago
Can someone help me with this equation: (4 x 11 5/8) + (3 x 11 3/4) + (5 x 11 7/8) + (5 x 12) + (2 x 12 1/8) = ?
sveta [45]

Answer:

225.375

that's what I got

3 0
3 years ago
What is the domain and range of this function?
max2010maxim [7]

As for the domain, the only restriction comes from the logarithm. The argument of a logarith must be strictly positive, so we have

x-2>0 \iff x>2

As for the range, we have:

  • The range of \log(x) are all real numbers
  • If we change to \log(x-2) we're translating the function horizontally, so the range remains the same
  • If we change to \log(5(x-2() we're stretching the function horizontally, so the range doesn't change
  • If we change to \log(5(x-2))+1 we're translating the function 1 unit up, but the range is already all the real numbers, so it doesn't change.

5 0
3 years ago
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