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KIM [24]
3 years ago
10

Solve 240 = 6z + c for 'c'. show steps please

Mathematics
1 answer:
Lunna [17]3 years ago
6 0

There are two ways to find or determine for the value of c. In the first method, we can use addition and subtraction to isolate the variable c from the other variables. In the second method, we can use the transposition of variables to isolate the variable c from the other variables.

So solving for the value of c:

 

<span>Using 1st method: Addition and Subtraction</span>

We are given:

240 = 6 z + c

Simply subtract 6 z on both sides:

240 – 6 z = 6 z + c – 6 z

Cancelling 6 z – 6 z on the right side:

240 – 6 z = c

or

c = 240 – 6 z

 

<span>Using the 2nd method: Transposition</span>

240 = 6 z + c

What we are going to do here is to simply transpose the variable 6 z from the right side to the left side of the equation so that we are left with c alone on the right side. Always remember that when we transpose, the symbol becomes opposite. That is:

240 + (- 6 z) = c

240 – 6 z = c

or

<span>c = 240 – 6 z</span>

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PLS SHOW how to do problem2!!
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Answer:

10 years, 3 months

Step-by-step explanation:

To answer this, use the compound amount formula:

A = P(1+r/n)^(nt), where r is the annual interest rate as a decimal fraction, n is the number of compounding periods, and P is the initial amount.  t represents the number of years.

Using the given info, we write $10,000 = $4,000(1 + 0.09/12)^(12*t) and set out to find the value of t, which represents the number of years necessary for the initial $4,000 to reach the end amount $10,000.

Let's solve 10000 = 4000(1 + 0.09/12)^(12 t) for t, as follows:

Divide both sides of this equation by 4000, to obtain an equation for (1 + 0.09/12)^(12 t):

2.5 = (1 + 0.09/12)^(12 t)

Simplifying the quantity inside the first set of parentheses, we get

2.5 = (1+ 0.0075)^(12*t), or 2.5 = 1.0075^(12*t)

Taking the log of both sides will eliminate the exponent (12*t):

log 2.5 = 12*t*log 1.0075.  Solve this for t by dividing both sides of this equation by 12*log 1.0075:

 log 2.5 * t             0.39794

-------------------- = ---------------------- = 10.2191 = t

12*log 1.0075      12*(0.003245)

$4,000 left in this account paying 9% with monthly compounding will increase to $10,000 after 10.22 years (10 years, 3 months)


8 0
3 years ago
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