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1 year ago

Expand (x – 4)^5 using the Binomial Theorem and Pascal’s triangle

Mathematics

1 answer:

worty [1.4K]1 year ago

7 0

$5th \: row = 1 \: \: \: 5 \: \: \: 10 \: \: \: 10 \: \: \: 5 \: \: \: 1$

$(x - 4) {}^{5} = x {}^{5} + 5x {}^{4} ( - 4) {}^{1} + 10x {}^{3} ( - 4) {}^{2} + 10x {}^{2} ( - 4) {}^{3} + 5x( - 4) {}^{4} + ( - 4) {}^{5}$

$(x - 4) {}^{5} = x {}^{5} - 20x {}^{4} + 160x {}^{3} - 640x {}^{2} + 1280x - 1024$

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Can anyone help me with this question please.

julsineya [31]

It’s d, because thats the formula !! mark me brainliest so I can help more people please !!

4 0

3 years ago

What is the length of the line segment with end points (5, -7) and (5, 11)

Law Incorporation [45]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points (5, -7) and (5, 11). Substitute:

$d=\sqrt{(5-5)^2+(11-(-7))^2}=\sqrt{0^2+18^2}=\sqrt{18^2}=18$

4 0

2 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

Solve for x 6(x-1)=9(x+2)

tigry1 [53]

<span>Simplifying 6(x + -1) = 9(x + 2) Reorder the terms: 6(-1 + x) = 9(x + 2) (-1 * 6 + x * 6) = 9(x + 2) (-6 + 6x) = 9(x + 2) Reorder the terms: -6 + 6x = 9(2 + x) -6 + 6x = (2 * 9 + x * 9) -6 + 6x = (18 + 9x) Solving -6 + 6x = 18 + 9x Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-9x' to each side of the equation. -6 + 6x + -9x = 18 + 9x + -9x Combine like terms: 6x + -9x = -3x -6 + -3x = 18 + 9x + -9x Combine like terms: 9x + -9x = 0 -6 + -3x = 18 + 0 -6 + -3x = 18 Add '6' to each side of the equation. -6 + 6 + -3x = 18 + 6 Combine like terms: -6 + 6 = 0 0 + -3x = 18 + 6 -3x = 18 + 6 Combine like terms: 18 + 6 = 24 -3x = 24 Divide each side by '-3'. x = -8 Simplifying x = -8</span>

8 0

2 years ago

Read 2 more answers

can someone explain it to me, i don't need the answer, i just need an detailed explanation of how they got the answer using the

zubka84 [21]

Answer:

Step-by-step explanation:

Good idea to review quadratic functions and the quadratic formula.

Quadratics have three coefficients: ax² + bx + c, and the "discriminant" is defined as b²-4ac. Please review these rules:

1) if the discriminant is +, the quadratic equation has two real, unequal roots.

2) if the disc. is 0, the equation has two real, equal root.

3) If the disc. is - , the equation has two complex roots.

Here a = 1, b = -3 and c = 4. Therefore the discriminant is (-3)²-4(1)(4), or

-7. Rule 3) applies: the equation has two complex roots, but no real ones. Thus we know that the graph does not cross the x-axis.

Graphing the given quadratic, x² - 3x + 4, using a dashed "line," is helpful. As you can see in the illustration of this graph, the graph neither touches nor crosses the x-axis. Thus, y = x² - 3x + 4 is greater than 0 for all x. The answer: All real numbers.

4 0

2 years ago