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rodikova [14]
3 years ago
15

Please answer quick in test!

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

The first one

Step-by-step explanation:

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⠀⠀⠀⠀⠀⠀⠀⠀⢀⣴⣿⡿⠛⠉⠙⠛⠛⠛⠛⠻⢿⣿⣷⣤⡀⠀⠀⠀⠀⠀

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⠀⠀⠀⠀⠀⠀⠀⣸⣿⡏⠀⠀⠀⣠⣶⣾⣿⣿⣿⠿⠿⠿⢿⣿⣿⣿⣄⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⣿⣿⠁⠀⠀⢰⣿⣿⣯⠁⠀⠀⠀⠀⠀⠀⠀⠈⠙⢿⣷⡄⠀

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⠀⢸⣿⡇⠀⠀⣿⣿⡇⠀⠀⠀⠀⠹⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⠃⠀

⠀⣸⣿⡇⠀⠀⣿⣿⡇⠀⠀⠀⠀⠀⠉⠻⠿⣿⣿⣿⣿⡿⠿⠿⠛⢻⣿⡇⠀⠀

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⠀⠀⠛⢿⣿⣿⣿⣿⣇⠀⠀⠀⠀⠀⣰⣿⣿⣷⣶⣶⣶⣶⠶⠀⢠⣿⣿⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⣿⣿⠀⠀⠀⠀⠀⣿⣿⡇⠀⣽⣿⡏⠁⠀⠀⢸⣿⡇⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⣿⣿⠀⠀⠀⠀⠀⣿⣿⡇⠀⢹⣿⡆⠀⠀⠀⣸⣿⠇⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⢿⣿⣦⣄⣀⣠⣴⣿⣿⠁⠀⠈⠻⣿⣿⣿⣿⡿⠏⠀⠀⠀⠀

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A cooler has a temperature of 32 degrees Fahrenheit. A bottled drink is placed in the cooler with an initial temperature of
FinnZ [79.3K]

Answer:

k \approx 0.44

Step-by-step explanation:

Given function:

f(t) = (ce)^{-kt}+32

As per question statement:

Initial temperature of bottle is 70 ^\circ F.

i.e. when time = 0 minutes, f(t) = 70 ^\circ F

70 = ce^{-k\times 0}+32\\\Rightarrow 38 = ce^{0}\\\Rightarrow c = 38

After t = 3, f(t) = 42^\circ F

42 = 38 \times e^{-k\times 3}+32\\\Rightarrow 42-32 = 38 \times e^{-3k} \\\Rightarrow 10  = 38 \times e^{-3k} \\\Rightarrow e^{3k} = \dfrac{38}{10}\\\Rightarrow e^{3k} = 3.8\\\\\text{Taking } log_e \text{both the sides:}\\\\\Rightarrow log_e {e^3k} = log_e {3.8}\\\Rightarrow 3k \times log_ee=log_e {3.8}   (\because log_pq^r=r \times log_pq)\\\Rightarrow 3k \times 1=log_e {3.8}\\\Rightarrow 3k = 1.34\\\Rightarrow k = \dfrac{1.34}{3}\\\Rightarrow k \approx 0.44

Hence, the value is:

k \approx 0.44

8 0
3 years ago
PLEASE HELP ME.....
Virty [35]

Answer:

They would meet each other at 01 : 24 PM.

Step-by-step explanation:

  • Erik took a trip to see his friend Mike who lives 308 miles away.
  • He left his place at 10 AM driving at 70 mph.
  • In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph.

As Erik left his house at 10 AM driving at 70 mph and in 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. It means

Erik left his place at 12:00 PM noon.

so, at 12:00 PM Erik had already traveled:

                                                                      2\times 70=140\:\:miles

Miles left =308-140=168\:\:miles

Let 't' be the time when they meet

so

70t\:+\:50t\:=168

120t=168

\mathrm{Divide\:both\:sides\:by\:}120

\frac{120t}{120}=\frac{168}{120}

t=\frac{7}{5}

so

t=\frac{7}{5}=1.4\:\:hours

or 1 hour and 24 minutes after 12:00 noon

i.e.

12\:+\:1.4\:=1\:O'clock\:+\:24\:minutes

Therefore, they would meet each other at 01 : 24 PM.

7 0
3 years ago
Use a proportion to solve the problem. Round to the nearest tenth as needed. A triangle drawn on a map has sides of lengths 9 cm
Volgvan
X/15=101/9
x= 505/3
x= 168.3 
8 0
3 years ago
Will give brainliest if this math question is answered correctly
solniwko [45]

Answer:  37 fruit pies+42 fruit juices=79 total items

(a) 37*1.65= $61.05

    42*1.36= $57.12

(b) Mr Sanchez's class earned more money.

(c) Mr. Sanchez's class earned $3.93 more than Mr. Kelly's class

    $61.05-$57.12= $3.93


Step-by-step explanation:


6 0
3 years ago
A taxicab charges $1.85 for the first quarter-mile and then $0.25 for every quarter mile after the first. The cost for a 17.5 mi
Roman55 [17]

Answer:

$19.10

Step-by-step explanation:

So since he charges $1.85 for the first quarter mile we can keep that as it is for now. If we add 0.25 4 times to make it $1 that would be a mile. We just have to add $17.25 plus the original $1.85 fee

8 0
2 years ago
Read 2 more answers
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