I think the answer is B.78Degrees
Answer:
This means that the correct initial value problem for the population p(t) as a function of time is is 
Step-by-step explanation:
The population of a town increases at a rate proportional to its population:
This means that this situation is modeled by the following differential equation:

In which k is the growth rate.
By separation of variables, the solution is given by:

In which P(0) is the initial population.
Initial population of 1000.
This means that the correct initial value problem for the population p(t) as a function of time is is 
Answer:
57.5
Step-by-step explanation:
The expected frequency of West Campus and Failed :
Let :
Failed = F
East Campus = C
West Campus = W
Passed = P
Frequency of FnW :
[(FnE) + (FnW) * (PnW) + (FnW)] / total samples
[(52 + 63) * (63 + 37)] / 200
[(115 * 100)] / 200
11500 / 200
= 57.5
n(Failed n East campus)
Answer:
x+4y=8
Step-by-step explanation:
graph shown below
Answer:
<u><em>13.896 kg</em></u>
Step-by-step explanation:
Volume of Gold Bar = Area of [Trapezium x Length of Bar]
Length of Bar = 16 cm
Area of Trapezium = 2 × Area of Triangle + Area of Rectangle
Area of Triangle = 0.5 × 5 × 3 = 7.5 cm²
2 × Area of Triangle = 2 × 7.5 = 15 cm²
Area of Rectangle = 6 × 5 = 30 cm²
Area of Trapezium = 15 + 30 = 45 cm²
Volume of Gold Bar = 45 × 16 = 720 cm³
Density of Gold = 19.3 g/cm³
Mass of Gold Bar = 720 × 19.3 = 13896 g = 13.896 kg
Mass of Gold Bar = 13.896 kg
Therefore the <u>mass</u> of the Gold Bar is: <em><u>13.896 kg</u></em> (kilograms).