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Andrew [12]
2 years ago
8

P^2=mx/t-t^2x make x the subject

Mathematics
1 answer:
belka [17]2 years ago
4 0

Answer:

x=\frac{P^2t}{(m-t^3)}

Step-by-step explanation:

P^2=\frac{mx}{t} -t^2x\\\\P^2+t^2x=\frac{mx}{t}\\\\t(P^2+t^2x)=mx\\\\P^2t+t^3x=mx\\\\P^2t=mx -t^3x\\\\P^2t=x(m-t^3)\\\\\frac{P^2t}{(m-t^3)} =\frac{x(m-t^3)}{(m-t^3)} \\\\\frac{P^2t}{(m-t^3)}=x

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The time it takes to charge the battery of a cell phone is directly proportional to the charge of the battery.
goldenfox [79]

Answer:

4 i believe

Step-by-step explanation:

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8 0
2 years ago
How can these models be used to find the sum 1.8 + 1.56?
enyata [817]

Answer:

The sum of  1.8 and 1.56 is 3.36 according to the model

Sum of decimals

Given the expression  1.8 + 1.56

Using the partial sum method

1.8 + 1.56 = (1.0 + 0.8) + (1.0+0.56)

Regroup as whole and decimal number

1.8 + 1.56 = (1.0 + 1.0) + (0.8 +0.56)

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3 0
2 years ago
(9 • 27)^1/2<br> A.) 9<br> B.)3radical3<br> C.) 9radical3<br> D.)27
kobusy [5.1K]
(9 \times 27)^ \frac{1}{2}  =  \sqrt{9 \times 27} = \sqrt{9 \times 3 \times 9} = 9 \sqrt{3}

Answer: 9√3
6 0
3 years ago
What is the distance between p(-300, 200) and Q(500, 400)?
alina1380 [7]

Answer:

200 √17

Step-by-step explanation:

distance between two points (x,y) and (x',y')

D² = (x' - x)² + (y' - y)²

D² = (500 - (-300))² + (400 - 200)² = 640000 + 40000 = 680000

D = √680000 = √4 x 17 x 10000 = 200 √17

7 0
3 years ago
Write the standard form of the equation of the line passing through the point (1, 5) and perpendicular to the line 4x - 7y = – 2
aleksley [76]

Answer:

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Step-by-step explanation:

4x-7y=-28

25xy

4 0
3 years ago
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