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1 year ago

P^2=mx/t-t^2x make x the subject

Mathematics

1 answer:

belka [17]1 year ago

4 0

Answer:

$x=\frac{P^2t}{(m-t^3)}$

Step-by-step explanation:

$P^2=\frac{mx}{t} -t^2x\\\\P^2+t^2x=\frac{mx}{t}\\\\t(P^2+t^2x)=mx\\\\P^2t+t^3x=mx\\\\P^2t=mx -t^3x\\\\P^2t=x(m-t^3)\\\\\frac{P^2t}{(m-t^3)} =\frac{x(m-t^3)}{(m-t^3)} \\\\\frac{P^2t}{(m-t^3)}=x$

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oee [108]

Answer:

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2 years ago

Solve each equation 3x^2=80

Lapatulllka [165]

Answer:

$x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}$

$x = \frac{\pm4\sqrt{15}}{3}$

Step-by-step explanation:

Hello!

Use the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

First, let's convert our equation to standard form of a Quadratic: ax² + bx + c = 0

3x² = 80

3x² - 80 = 0

Note, thats the value of b will be 0, as there is no "bx"

Now, solve:

$x = \frac{-(0) \pm \sqrt{(0)^2 - 4(3)(-80)}}{2(3)}$ Plug in values
$x = \frac{\pm\sqrt{960}}{6}$ Simplify the radical (Discriminant)
$x = \frac{\pm8\sqrt{15}}{6}$ Pull out perfect squares
$x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}$ Reduce factors

The solutions are $x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}$

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2 years ago

If y equals -18 when x is 6 find x when y is 6

Mekhanik [1.2K]

Answer:

x=-2

Step-by-step explanation:

-6/18=x/6

simplify the -6/18 into -1/3,

-1/3=x/6

cross product,

3*x=-1*6

3x=-6

x=-6/3

x=-2

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2 years ago

On a string of red and blue lights, the red lights blink everyb3 seconds, and the blue lights blink every 5 seconds. How many ti

yuradex [85]

When will they blink together?
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3 years ago

What's the algebraic expression for the sum of v and 3

dangina [55]

The sum means addition
v + 3

6 0

3 years ago