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lana [24]
3 years ago
13

If a_1=2a 1 ​ =2 and a_n=(a_{n-1})^2-2a n ​ =(a n−1 ​ ) 2 −2 then find the value of a_4a 4 ​ .

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0

9514 1404 393

Answer:

  2

Step-by-step explanation:

We assume your recursive formula is ...

  a_1=2\\a_n=a_{n-1}^2-2

Using this to find a4, we get ...

  a_2=a_1^2-2=2^2-2=2\\a_3=a_2^2-2=2^2-2=2\\a_4=a_3^2-2=2^2-2=2\\\\\boxed{a_4=2}

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(6 + 2i)(6 - 2i)=40

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Which shows a difference of squares?
d1i1m1o1n [39]

Answer:

The equations shows a difference of squares are:

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Step-by-step explanation:

the difference of two squares is a squared number subtracted from another squared number, it has the general from Ax² - By²

We will check the options to find which shows a difference of squares.

1) 10y²- 4x²

The expression is similar to the general form, so the equation represents a difference of squares.

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2) 6y²- x²

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3 years ago
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Answer:

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The uniform distribution has two bounds, a and b, and the expected value of the uniform distribution is given by:

E = \frac{a+b}{2}

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