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AVprozaik [17]
3 years ago
4

Which are perfect squares? Check all that apply. (Multiple Choice)

Mathematics
2 answers:
jeka943 years ago
6 0

Answer:

A,C,E,F

Step-by-step explanation:

A perfect square is what you get when you multiply 2 equal integers.

melamori03 [73]3 years ago
4 0

Answer: a, c e, f

Step-by-step explanation:

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If the probability of a chance event is 0.82, it is more likely to happen than which of the following probabilities of another c
Charra [1.4K]

Answer:

0.8

Step-by-step explanation:

Things to remember:

- You can add as many 0's on the end of a decimal and it will still equal the same number, as long as the 0's are on the right side of the decimal point. For example, 0.7 = 0.7000.

- The lowest value has the lowest probability

So, let's rewrite the options with the same amount of decimal points:

1.00

0.90

0.80

0.85

Now, find the value under 0.82. In this option, the lowest value is 0.80, and it is under 0.82, so it is the answer.

8 0
4 years ago
Hellpppppppppp show proof​
ELEN [110]

3 ×+8y=0

Step-by-step explanation:

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8 0
3 years ago
Help!! PLEASE!!!???!!!
sdas [7]
1.) Just divide the numbers. 45/3=15. Letter D.
2.) 10(2.50)=25. Letter C.
3.) 7(3)=21. Letter C.
4.) 3/2=1.5. 1.5(15)=22.5. Letter B.
5.) Letter B
6.) Letter B.
7.) 189.50(.06)= 11.37. 189.50+11.37= Letter D.
8.) 1.50(.35)= .525. 1.50-.525= 0.975. Letter C.
9.) Letter A
10.) Letter C
5 0
3 years ago
Nananansbanansnnsnsbdbbxbsbshshsbsbsbsbbsbsbsbsbs please help ?
AveGali [126]

Answer:

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Step-by-step explanation:

4 0
3 years ago
the length of a rectangle is 6 inches longer than its width. If the perimeter of the rectangle is 76in. Find its length and widt
DerKrebs [107]

The length and the width of the rectangle are 22 inches and 16 inches respectively

<h3>How to determine the length and the width of the rectangle?</h3>

The given parameters are:

Length = 6 inches + width

Perimeter = 76 inches

The perimeter is calculated as:

Perimeter = 2 * (Length + Width)

This gives

76 inches = 2 * (6 inches + Width + Width)

Divide through by 2

38 inches = 6 inches + Width + Width

Evaluate the like terms

2 * Width = 32 inches

Divide both sides by 2

Width = 16 inches

Substitute Width = 16 inches in Length = 6 inches + width

Length = 6 inches + 16 inches

Evaluate

Length = 22 inches

Hence, the length and the width of the rectangle are 22 inches and 16 inches respectively

Read more about perimeters at:

brainly.com/question/24571594

#SPJ1

4 0
2 years ago
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