A=number of seats in section A
B=number of seats in section B
C=number of seats in section C
We can suggest this system of equations:
A+B+C=55,000
A=B+C ⇒A-B-C=0
28A+16B+12C=1,158,000
We solve this system of equations by Gauss Method.
1 1 1 55,000
1 -1 -1 0
28 16 12 1,158,000
1 1 1 55,000
0 -2 -2 -55,000 (R₂-R₁)
0 12 16 382,000 (28R₁-R₂)
1 1 1 55,000
0 -2 -2 -55,000
0 0 4 52,000 (6R₂+R₃)
Therefore:
4C=52,000
C=52,000/4
C=13,000
-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.
A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.
Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
Answer:
570yd^2
step by step:
Split the backyard into 2 different rectangles and add the areas together. I did 8x30 and 15x22.
Answer:
10^0*10^1-1,
10^0*10^1*1^10,
10^0+10^1*1^10,10^0+10^1+1^10
Step-by-step explanation:
Let's say the speed of the plane is "p", and the speed of the wind is "w".
when the plane goes with the wind, is not really going "p" mph fast, is really going "p + w" mph fast, because the wind is adding speed to it.
likewise when the plane is going against the wind, is also not going "p" fast is going "p - w" mph fast. Therefore,