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Viktor [21]
2 years ago
10

2/3 b + 5 =20 - b solve for b

Mathematics
2 answers:
Alborosie2 years ago
8 0

Answer:

b = 9

Step-by-step explanation:

\frac{2}{3} b + 5 = 20-b\\\frac{2}{3} b+5+b=20-b+b\\\frac{5}{3} b+5=20\\\frac{5}{3} b+5-5=20-5\\\frac{5}{3}b=15\\b= 15*\frac{3}{5} \\b= 9

Wittaler [7]2 years ago
4 0

Answer:

b = 9

Step-by-step explanation:

\frac{2}{3} b + 5 = 20 - b

In order to solve for b, we must isolate the variable. We can start by subtracting 5 from both sides.

\frac{2}{3} b + 5 - 5 = 20 - b - 5

Simplify.

\frac{2}{3} b = 15 - b

Add b to both sides.

\frac{2}{3} b + b = 15 - b + b

Simplify.

\frac{2}{3} b + b = 15

Multiply everything by 3 to remove the fractions.

3(\frac{2}{3}b+b) = 3(15)

Simplify.

2b + 3b = 45

Simplify.

5b = 45

Divide 5 from both sides.

5b ÷ 5 = 45 ÷ 5

Simplify.

b = 9

For more information on solving variables, check out the following answers!

  • brainly.com/question/633344
  • brainly.com/question/1267151
  • brainly.com/question/4207498
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Solution:

Volume of a cuboid is:

V=l\times b\times h

Where, l is length, b is breadth and h is the height.

The volume of the tank is :

V=4\times 2.5\times 2.4

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Volume of tank is 24 cubic meter.

One third of the tank is filled with water. So, the volume of the water is

\dfrac{24}{3}=8

The volume of water is 8 cubic meters.

We have,

1 cubic meter = 1000 liters.

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Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

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Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

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Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

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