Y-5=3-9 (y+2)
Solve for y
Distribute the 9 to (y+2)
Y-5=3-9y-18
Y-5=-15-9y
+9y to both sides
10y-5=-15
+5 to both sides
10y=-10
÷10 both sides
Y= -1
2 (x-7)-10=12-4x
Solve for X
Distribute 2 to (x-7)
2x-14-10=12-4x
2x-24=12-4x
+4x to both sides
6x-24=12
+24 to both sides
6x=36
÷6 to both sides
X=6
In probability, there are hint clues that you must be vigilant of. When it tells you to find the probability of event 1 'or' event 2, you must ADD their individual probabilities. When it tells you to find the probability of event 1 'and' event 2, you must MULTIPLY their individual probabilities.
Now, you have two dices. You are asked to find the probability of getting a face of 3, 4 or 5. The probability of each face of a dice is 1/6, because there are a total of 6 faces. When you use two dices, it becomes 2/12 or still 1/6. So, the total probability of getting either 3, 4 or 5 is: 1/6 + 1/6 + 1/6 = 1/2. However, you still have to multiply this with the total probability of getting a prime numbers which are 1, 2, 3 and 5. Thus, 1/6 + 1/6 + 1/6 + 1/6 = 2/3
Hence, the total probability would be 1/2 * 2/3 = 1/3 or 33%
Yes he and his family have a good day tomorrow and I will let you the mason jar of the money he is going we I am so sorry I just need points for the questions
W=4 that the answer !!!!!
