The roots are just the zero value of the formula. To find these, we factor:
(x - 2)(x - 2)
(x - 2)^2
to make this into a zero, we set x-2 = 0, then solve for x
x = 2
If x = 2, then the brackets = 0, and those are the roots
The roots are x = 2
Leave a comment if you couldn’t understand, and I’ll try to answer.
Step-by-step explanation:
all you have to do is multiply all those numbers together so 0.5 * 4.2 * 2.8 *7 =41.16
the process the exact same for all the other ones they have all your stuff set out for you on each one of the shapes
Just like at any other time, to add/subtract fractions you need a common denominator.
14)
1/(x^2+2x)+(x-1)/x=1 so we need a common denominator of x(x^2+2x)
[1(x)]/(x(x^2+2x))+[(x-1)(x^2+2x)]/(x(x^2+2x))=[1(x(x^2+2x))]/(x(x^2+2x))
now if you multiply both sides of the equation by x(x^2+2x) you are left with:
x+(x-1)(x^2+2x)=x(x^2+2x)
x+x^3+2x^2-x^2-2x=x^3+2x^2
x^3+x^2-x=x^3-2x^2
x^2-x=-2x^2
3x^2-x=0
x(3x-1)=0, x=0 is an extraneous solution as division by zero is undefined. So the only real solution is:
x=1/3
...
16)
(r+5)/(r^2-2r)-1=1/(r^2-2r) the common denominator we need r^2-2r so
[r+5-1(r^2-2r)]/(r^2-2r)=1/(r^2-2r), multiplying both sides by r^2-2r yields:
r+5-r^2+2r=1
-r^2+3r+5=1
-r^2+3r+4=0
r^2-3r-4=0
(r-4)(r+1)=0, r^2-2r cannot equal zero, r(r-2)=0, r cannot equal 0 or 2...
r=-1 or 4
Answer:
CD = 3
Step-by-step explanation:
Given 2 secants from an external point to the circle, then
CB × CA = CD × CE , that is
4 × (4 + 6.5) = CD × 14
4 × 10.5 = 14CD
42 = 14CD ( divide both sides by 14 )
CD = 3
Answer:
41
Step-by-step explanation:
Given x = -2,
Substitute x into the expression.
