X^(3/5) = 1.84
x^(3/5) = (1.84)
Raise both sides of the equation to (5/3).
This is so that on the side with x, 3/5 * 5/3 = 1.
(x^3/5 )^5/3 = (1.84)^(5/3)
x^(3/5 * 5/3) = 1.84^(5/3)
x^1 = 1.84^(5/3)
x = 1.84^(5/3)
But remember we are solving for x^2.
x = 1.84^(5/3)
x^2 = (1.84^(5/3))^2
x^2 = 1.84^(5/3 *2 )
x^2 = 1.84^(10/3)
Use a calculator here.
x^2 = 1.84^(10/3) ≈ 7.63
Option A.
Cheers!
Definitely irrational because the decimal never repeat
We are given with the variable cost which is:
q = -20s + 400
The selling price is 's'. So, the profit can be represented by:
P = qs - q(12)
Subsituting:
P = (-20s + 400)s - 12 (-20s + 400)
P = -20s^2 + 640s - 4800
To optimize this, we must differentiate the equation and equate it to zero, so:\
dP/ds = -40s + 640 = 0
Solving for s,
s = 16
So, the selling price should be $16 to optimize the yearly profit.
The answer is D could you give me brainlist
