Answer:
A. x≥4 ( red on 4)
B. x≤4 ( red on 4)
C. x>4 (blue on 4)
D. x<4 (blue on 4)
Step-by-step explanation:
illustrated
A. x≥4 ( red on 4)
B. x≤4 ( red on 4)
C. x>4 (blue on 4)
D. x<4 (blue on 4)
Answer:
(8,10) is not a solution
Step-by-step explanation:
Cuz it’s not on both inequality shaded part but just one of them and also when we substitute one is true and the other one is false
2x + y _< 8
2(8) + 10 _< 8
18 + 10 _< 8
28 _< 8 false
X + y _> 4
8 + 10 -> 4
18 _> 4 true
Answer:
The answer could be easier if you make a ratio and actual graph
Step-by-step explanation:
Q1 of company A = 2.5
Q3 of company A = 8
Interquatile range = (Q3 - Q1)/2 = (8 - 2.5)/2 = 5.5/2 = 2.75
Q1 of company B = 2
Q3 of company B = 5.5
Interquatile range = (5.5 - 2)/2 = 3.5/2 = 1.75
Therefore, t<span>he interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.</span>
So you will need to solve for x and y before evaluating 2x+y....
2x-y=9, y=2x-9 now this will make 4x^2-y^2=171 become:
4x^2-(2x-9)^2=171
4x^2-(4x^2-36x+81)=171
36x-81=171
36x=252
x=7, now we can use 2x-y=9 to solve for y...
2(7)-y=9
14-y=9
-y=-5
y=5
now we know that x=7 and y=5, 2x+y becomes:
2(7)+5
14+5
19
