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oksian1 [2.3K]
1 year ago
6

Help help help help help help help help help help help

Mathematics
1 answer:
kvasek [131]1 year ago
7 0

Solving the quadratic equation we conclude that:

  • The maximum height is 45ft.
  • The rocket is 18 seconds in the air.

<h3>How to get the maximum height of the rocket?</h3>

The height of the rocket is defined by the quadratic equation:

d = 90t - 5t^2

The maximum height is what we get in the vertex of the quadratic equation, such that for this quadratic equation, the vertex is at:

t = -90/(2*-5) = 9

So the maximum height is what we get when we evaluate in t = 9:

d = 90*9 - 5*9^2 = 45

The maximum height is 45ft.

<h3>How to get the time in the air?</h3>

Now we need to solve the equation for the largest value of t:

d = 90*t - 5t^2 = 0

Rewriting it, we get:

0 = 90*t - 5*t^2\\\\0 = t*(90 - t*5)

The maximum solution is what we get when:

0 = 90 - t*5

t = 90/5 = 18

The rocket is 18 seconds in the air.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

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