1. You can expand the coefficients to yield 6, and add the powers since the bases are the same (ie A)
2. y⁻² can also be rewritten as 1/y², so it becomes 1/y² · 1/y⁵ = 1/y⁷ (ie C)
3. Only the x is affected by the power.
4. y = 3·5ˣ doesn't change in slope, so it essentially is similar to a 5ˣ graph.
5. Should be pretty straight forward. 6. Should be pretty straight forward. 7. Should be pretty straight forward.
8. Since x is the length of the border, calculate the area of the frame and subtract that from the area of the square painting. (Remember that the length of the square painting is x - 8, not x - 4)
9. Should be pretty straight forward. 11 - 25 are pretty much similar to each other. If you have trouble, let me know and I'll walk you through it.
Calculate the area of the frame and subtract that from the area of the square painting. (Remember that the length of the square painting is x - 8, not x - 4)
Any point that is co planar with one another and is also equidistant from a given point is a circle. We need it to be co planar, otherwise it would be 3-dimensional and create a sphere. And if they we not all equidistant, they would not make an even circle (it'd be an oval or another shape).
