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stich3 [128]
2 years ago
10

the earth orbits is oval in shape.explain how the mangnitude of gravitational between the earth and sun changes as the eart move

s from position a to b
Physics
1 answer:
s2008m [1.1K]2 years ago
6 0

As the distance between the Earth and the Sun decreases, the magnitude of gravitational force between the earth and sun increases and vice versa.

<h3>What is gravitational force?</h3>

Gravitational force is a force that attracts any two objects with mass.

According to Newton's law of universal gravitation, the force of attraction between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects.

F = Gm₁m₂/R²

where;

  • m₁ is mass of Earth
  • m₂ is mass of sun
  • R is the distance between the Earth and Sun

Thus, as the distance between the Earth and the Sun decreases, the magnitude of gravitational force between the earth and sun increases and vice versa.

Learn more about gravitational force here: brainly.com/question/72250

#SPJ1

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Help please, I don't get it​
Sergio [31]

Answers:

a) \hat F=(0.83,-0.55) N

b) \hat D=(-0.44,-0.89) m

c) \hat V=(-0.47,0.88) m/s

Explanation:

A unit vector is a vector whose magnitude (length) is equal to 1. This kind of vector is identified as \hat v and the way to calculate is as follows:

\hat v=\frac{\vec v}{|v|}

Where:

\vec v=(x,y) is the vector

|v|=\sqrt{x^{2}+y^{2}} is the magnitude of the vector

Having this information clarified, let's begin with the answers:

a) Force Vector

\vec F=(9.0 \hat i - 6.0 \hat j) N

Magnitude of \vec F:

|F|=\sqrt{(9.0 \hat i)^{2}+(-6.0 \hat j)^{2 }}N=10.81 N

<u />

<u>Unit vector:</u>

\hat F=\frac{\vec F}{|F|}

\hat F=\frac{(9.0 \hat i - 6.0 \hat j) N}{10.81 N}

\hat F=\frac{9.0}{10.81} N-\frac{6.0}{10.81}N

\hat F=(0.83,-0.55) N

b) Displacement Vector

\vec D=(-4.0 \hat i - 8.0 \hat j) m

Magnitude of \vec D:

|D|=\sqrt{(-4.0 \hat i)^{2}+(-8.0 \hat j)^{2 }}m=8.94 m

<u />

<u>Unit vector:</u>

\hat D=\frac{\vec D}{|D|}

\hat D=\frac{(-4.0 \hat i - 8.0 \hat j) m}{8.94 m}

\hat D=\frac{-4.0}{8.94} Nm+\frac{-8.0}{8.94}m

\hat D=(-0.44,-0.89) m

c) Velocity Vector

\vec V=(-3.50 \hat i + 6.50 \hat j) m/s

Magnitude of \vec V:

|V|=\sqrt{(-3.50 \hat i)^{2}+(6.50 \hat j)^{2}}m/s=7.38 m/s

<u />

<u>Unit vector:</u>

\hat V=\frac{\vec V}{|V|}

\hat V=\frac{(-3.50 \hat i +6.50 \hat j) m/s}{7.38 m/s}

\hat V=\frac{-3.50}{7.38} m/s+\frac{6.50}{7.38}m/s

\hat V=(-0.47,0.88) m/s

8 0
4 years ago
Write 3 – 4 sentences predicting the changes in electrostatic force, strong nuclear force, and the stability of a nucleus if the
mrs_skeptik [129]

Electrostatic force arises due  the charges at rest.In a isolated atom there is three fundamental particles called electron,proton and neutron.the electron is negatively charged,proton is positively charged and the neutron is neutral.

Generally the force between electron and proton is attractive,there will be also repulsion between proton and proton.due to the strong nuclear forces atom main its stability In an stable atom the the neutron to proton ratio lies between 1 to 1.42.if the number of neutrons are increased more,the stability will be hampered resulting the decrease in nuclear force also.

As neutron is neutral,there will be no change in the electrostatic forces as there is no increment of charge.but when the neutron number is increased at that time the binding energy per nucleon is decreased which in turn affects the nuclear force which is a  short range force.the nucleus becomes heavy and unstable which undergoes decay.

one thing we have to remember also that the nuclear force is spin dependent .so the change in neutron number affects the strong nuclear force which is the reason for its decrement.

8 0
3 years ago
Force = mass times acceleration
Alona [7]

Yes indeed ! Very good !


3 0
3 years ago
May somebody help me in this.
aliina [53]

Answer:

answer c. come easy dear.

7 0
3 years ago
| A 1.0 kg stone is dropped from a bridge 100 m above a canyon. What will be the kinetic energy of the stone after it
Mnenie [13.5K]

Answer:

Option D

490 J

Explanation:

When at a height of 100 am above and released, the ball initially posses only potential energy. When it falls, some potential energy is converted to kinetic energy.

Initial potential energy= mgh where m is the mass, g is the acceleration due to gravity and h is height. Substituting 1 Kg for m, 9.81 for g and 100 m for h then

PE initial = 1*9.81*100= 981 J

At 50 m, PE will be 1*9.81*50=490.5 J

Subtracting PE at 50 m from initial PE we get the energy that has been converted to kinetic energy hence

981-490.5= 490.5 J

Approximately, 490 J

8 0
4 years ago
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