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kirza4 [7]
2 years ago
8

The staff at a company includes: 1 manager, 2 shift supervisors, 2 engineers, 10 technicians, and 25 production operators. If a

person is selected at random, what is the probability that he/she is a technician or production operator?
Mathematics
1 answer:
I am Lyosha [343]2 years ago
7 0

The probability of he/she is a technician or production operator will be 7/8.

<h3>What is probability?</h3>

The probability of an event occurring is defined by probability.

If you flip a coin, the likelihood that it will land on its head or tail is nothing more than the chance that either the head or the tail will occur.

Given,

Event 1 = selection of technician

Event 2 = selection of production operator

Since both events are independent and nothing has common in between

So,

P(1 or 2 ) = p(1) × p(2)

So,

probability (technician or production operator) = probability of technician × probability of production operator.

Probability (technician or production operator) = 10/40 + 25/40 = 7/8

Hence the probability of he/she is a technician or production operator will be 7/8.

For more information about the probability

brainly.com/question/11234923

#SPJ1

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\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

Explanation

\frac{1}{a+bi}=c+di

Step 1

multiplicate by the conjugate

\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

notice that

\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

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