3 years ago

Someone the answer pls

Mathematics

1 answer:

masha68 [24]3 years ago

8 0

Answer:

the yellow one

Step-by-step explanation:

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Let f(x)=x^2+17x+72<br><br><br><br> What are the zeros of the function?

densk [106]

Answer:

The zeros of the given function $f(x)=x^2+17x+72$ is $\left(x+8\right)\left(x+9\right)$ are -8 and -9.

Step-by-step explanation:

Given : Function $f(x)=x^2+17x+72$

We have to find the zeros of the functions.

Consider the given Function $f(x)=x^2+17x+72$

Since, we have to find the zeros of the given functions.

Put f(x) = 0

Thus, $x^2+17x+72=0$

We can solve the given equation using middle term splitting method.

17x can be written as 8x + 9x

$x^2+17x+72=0$ can be written as $x^2+8x+9x+72=0$

Taking x common from first two term and 9 common from last two terms, we have,

$x(x+8)+9(x+8)=0$

Simplify, we have,

$\left(x+8\right)=0$ or $(x+9\right)=0$

x = -8 and x = -9

Apply zero product rule, $a\cdot b= 0 \Rightarrow a=0 \ or \ b=0$

$\left(x+8\right)\left(x+9\right)=0$

Thus, The zero of the given function $f(x)=x^2+17x+72$ is $\left(x+8\right)\left(x+9\right)$ are -8 and -9.

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3 years ago