Answer:
Area of triangle = 15 square units
Step-by-step explanation:
We need to find area of the triangle, given the vertices:
A=(4,0)
B=(1,5)
C=(7,5)
The formula used is: 
We have: 
Putting values and finding area

We will be ignoring negative sign, because area of triangle is positive.
So, Area of triangle = 15
1.8 - 0.2x = -1.6 Subtract 1.8 on both sides
1.8 - 1.8 - 0.2x = -1.6 - 1.8
-0.2x = -3.4 Divide -0.2 on both sides

x = 17
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
The picture of the question in the attached figure
Part 1
Find the length side AB
we know that
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values

solve for AB

Part 2
Find the length side AC
we know that
----> by TOA (opposite side divided by the adjacent side)
substitute the given values

solve for AC
