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olga55 [171]
3 years ago
9

Help please!

Mathematics
1 answer:
daser333 [38]3 years ago
6 0
Since it is no more than 14 years, you would subtract 4 from 14 and get 10, the two numbers you would put the inequality symbol in between would be the 10 and the variable x. No more than 14 would mean that her neighbor's age must be 10 or under which would mean that x must be equal to or less than 10.
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X² -6 = 5x<br><br> what is x squared minus six equals five x
Fudgin [204]

Answer:

1x^2 -6=5x

1x-6=5x

-6=4x

-6/4x= -1.5

5 0
3 years ago
Use the decimals 2.47, 9.57 and 7.1 to write two different addition facts and two different subtraction facts
netineya [11]
2.47 + 7.1
7.1 + 2.47

9.57-7.1
9.57-2.47
6 0
3 years ago
PLEASE HELP!!! ASAP!!!!!!!!!!!!!!! 10 POINTS
I am Lyosha [343]
1800|2\\.\ 900|2\\.\ 450|2\\.\ 225|5\\.\ \ 45|5\\.\ \ \ 9|3\\.\ \ \ 3|3\\.\ \ \ 1|\\\\1880=2\cdot2\cdot2\cdot5\cdot5\cdot3\cdot3=2^3\cdot5^2\cdot3^2\\\\Answer:\ \boxed{2^3\cdot3^2\cdot5^2}

\sqrt[3]{320}\\\\320|2\\160|2\\.\ 80|2\\.\ 40|2\\.\ 20|2\\.\ 10|2\\.\ \ 5|5\\.\ \ 1|\\\\320=2\cdot2\cdot2\cdot2\cdot2\cdo2\cdot5=2^3\cdot2^3\cdot5=2^3\cdot2^3\cdot\\\\\sqrt[3]{320}=\sqrt[3]{2^3\cdot2^3\cdot5}=\sqrt[3]{2^3}\cdot\sqrt[3]{2^3}\cdot\sqrt[3]{5}=2\cdot2\sqrt[3]{5}=4\sqrt[3]5\\\\Answer:\ \boxed{\sqrt[3]{320}=4\sqrt[3]{5}}
4 0
3 years ago
Read 2 more answers
A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

4 0
2 years ago
On a coordinate plane, a line goes through (negative 3, 2) and (0, 1). A point is at (3, 4).
Amiraneli [1.4K]

Answer:

y = 3x - 5

Step-by-step explanation:

Points on given line: (-3, 2), (0, 1)

m1 = slope of given line; m = slope of perpendicular

Slope of given line = m1 = (y2 - y1)/(x2 - x1) = (2 - 1)/(-3 - 0) = 1/(-3) = -1/3

The slopes of perpendicular lines have a product of -1.

m1 * m = -1

-1/3 * m = -1

m = 3

Slope of perpendicular: m = 3

Point on perpendicular: (3, 4)

y - y1 = m(x - x1)

y - 4 = 3(x - 3)

y - 4 = 3x - 9

y = 3x - 5

Answer: y = 3x - 5

4 0
3 years ago
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