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Ainat [17]
2 years ago
5

38. For a field trip 11 students rode in cars and the rest rode in 8 busses with the same number of students on each. How many s

tudents were on each bus is 315 students went on the field trip.
Help I need an equation and an answer!!!!​
Mathematics
1 answer:
Natalija [7]2 years ago
4 0
8x+11=315 where x = the number of students on each bus
x = 38 students
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Given two functions f(x)=2x+4 and g(x)=−1/5x−3 , what is the function rule for (f+g)(x) ?
Angelina_Jolie [31]

The definition is pretty simple:

(f+g)(x) = f(x)+g(x)

So, we only have to sum the expressions:

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3 years ago
The area of another rectangle is x² + 5x + 6. If one side measures (x + 2), what is the measure of the other
tiny-mole [99]
  • L=x+2
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\\ \sf\longmapsto LB=Area

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2 years ago
Of the cars sold during the month of July, 89 had air conditioning, 99 had an automatic transmission, and 74 had power steering.
DedPeter [7]

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There are a total of 23 cars with air conditioning and automatic transmission but not power steering

Step-by-step explanation:

Let A be the cars that have Air conditioning, B the cars that have Automatic transmission and C the cars that have pwoer Steering. Lets denote |D| the cardinality of a set D.

Remember that for 2 sets E and F, we have that

|E \cup F| = |E| + |F| - |E \cap F|

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We now alredy the following:

|A| = 89

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|B \ (AUC)| = 65

|C \ (AUB)| = 26

|B \cap C| = 11

We want to know |(A∩B) \ C|. Lets calculate it by taking the information given and deducting more things

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99 = |B| = |B ∩ C| + |B∩C^c| = 11 + |B∩C^c|

Therefore, |B∩C^c| = 99-11 = 88

And |A ∩ B ∩ C^c| = |B∩C^c| - |B∩C^c∩A^c| = |B∩C^c| - |B \ (AUC)| = 88-65 = 23.

This means that the amount of cars that have both transmission and air conditioning but now power steering is 23.

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Step-by-step explanation:

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