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Gelneren [198K]
2 years ago
12

Which of the following is an equation for the plane through the point (1, 1, −1) and parallel

Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0

The given plane, x-y+z=3, has normal vector \vec n = \langle1,-1,1\rangle. Any plane parallel to this one has the same normal vector.

Let (x,y,z) be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

\langle x,y,z\rangle - \langle 1,1,-1\rangle = \langle x-1, y-1, z+1 \rangle

and this is perpendicular to \vec n.

So the equation of the plane is

\langle x-1, y-1, z+1 \rangle \cdot \vec n = 0 \implies (x-1) - (y-1) + (z+1) = 0 \implies \boxed{x - y + z = -1}

or equivalently,

\boxed{-x + y - z = 1}

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I am confused. what is 5r– 7 = 2r+ 14
Vlada [557]

Answer:

r=7

Step-by-step explanation:

5r-7=2r+14

add sevento both sides

5r=2r+21

Subtract 2r from both sides.

3r=21

divide both sides by 3

r=7

5 0
3 years ago
Lee spent $36 to purchase a combination of drinks, sandwiches, and chips for himself and his friends. A drink costs $2, a sandwi
valkas [14]

2x+4y+0.50z=36 represents the situation.

Step-by-step explanation:

Let,

Drinks = x

Sandwich = y

And,

Chips = z

Total amount on these items = $36

According to the statement;

x(cost\ of\ one\ drink)+y(cost\ of\ one\ sandwich)+z(cost\ of\ one\ chips)=\ Total\ amount\ spent\\2x+4y+0.50z=36

2x+4y+0.50z=36 represents the situation.

Keywords: Linear equations

Learn more about linear equations at:

  • brainly.com/question/10081622
  • brainly.com/question/10341324

#LearnwithBrainly

7 0
3 years ago
Convince me why points B&C are solutions to this system of linear inequalities.
muminat
The coordinates of B and C are solutions to the system of inequalities because both are true to the two inequalities. A is not a solution to the system of inequalities because it is only true to “y is less than or equal to 2x”.
3 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD=√2 cm.
Zielflug [23.3K]

Given that triangle ABC is right angle triangle. CD is altitude such that AD=BC

ABC is a right angle triangle so apply Pythogorean theorem

AC^{2} + BC^{2} = AB^{2}

AC^{2} + AD^{2} = AB^{2}      (Given that AD = BC)

AC^{2} + AD^{2} = 3^{2}      (Given that AB=3)

AC^{2} + AD^{2} = 9 ...(i)

ADC is a right angle triangle so apply Pythogorean theorem

AD^{2} + CD^{2} = AC^{2}

AD^{2}+(\sqrt{2})^2= AC^{2}

AD^{2}+2= AC^{2}

AD^{2}=AC^{2} -2 ...(ii)


Plug value (ii) into (i)

AC^{2} + AC^{2}-2 = 9

2AC^{2} -2=9

2AC^{2} =11

AC^{2} =\frac{11}{2}

AC=\sqrt{\frac{11}{2} }


Hence final answer is AC=\sqrt{\frac{11}{2} }

8 0
3 years ago
Read 2 more answers
Why cant i see the answer i cant fot brainly i dont have money like that
liraira [26]

Answer:

just make an account

Step-by-step explanation:

3 0
3 years ago
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