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2 years ago

The O2 molecule breaks apart at lower wavelengths than the O3 molecule. What is the main reason for this?

Chemistry

1 answer:

kozerog [31]2 years ago

8 0

The main reason for this is Average bond of O₂ is shorter and strong from O₃.

<h3>What is ozone?</h3>

Ozone is a blue gas composed of three oxygen atoms bonded together.

It occurs naturally high up in the Earth's atmosphere, where it protects the surface from harmful ultraviolet (UV) rays,

UV radiation will dissociate ozone into an oxygen atom and an oxygen molecule.

Ozone molecules are tetrahedral so the bond angle is 109 degree the electrons in the double bond occupy more space that the non-bonding electron pair.

Oxygen has a small size that leads to smaller O-O bond length.

A lone pair of electrons on both the oxygen repel each other leading to weakening of O-O bond.

O3 has longer and weaker bonds than O2, whereas SO2 has shorter and stronger bonds than SO.

Molecular oxygen, O2, is photolyzed by light of 241 nm and has a bond energy of 498 kJ/mol.

The main reason for this is Average bond of O₂ is shorter and strong from O₃.

Learn more about ozone, Here:

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3 years ago

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jenyasd209 [6]

Answer:

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Explanation:

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that is known as IUPAC naming system. According to it

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3 years ago

Read 2 more answers

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3 years ago

Will a precipitate form (yes or no) when 50.0 ml of 1.2 × 10–3 m pb(no3)2 are added to 50.0 ml of 2.0 × 10–4 m na2s? if so, iden

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Answer:

Yes, a precipitate of PbS forms

Explanation:

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The lead sulfide forms a precipitate in the aqeous solution.

Precipitation is a form of reaction in which ions combines to form a solid precipiate. Most double displacement reactions in which ionic compounds are the reactants results in formation of a precipitate as the product.

There are rules of solubility which guides a reaction that would lead to the formation of a precipitate. The mos applicable of the rules to the reaction stated above is that "carbonates, phosphates, sulfides, oxides and hydroxides are insolube". The sulfide of lead formed in the product is therefore insoluble.

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3 years ago

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